you have to use all 11
2006-08-09 14:18:52 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
it is 11C5,combination of 11 taking 5 at a time
=11*10*9*8*7/1*2*3*4*5=11*3*2*7=462 teams
2006-08-09 14:51:02 · answer #1 · answered by raj 7 · 0⤊ 1⤋
6 x 5 = 30 teams
2006-08-09 14:26:34 · answer #2 · answered by Danny La Cuesta 1 · 0⤊ 1⤋
I believe there are 45 possibilities. If you line the positions up like this:
a b c d e
There are 11 players that can go into slot a, once a player is in slot a, there are now 10 that can go in slot b, then 9 in c, 8 in d, and 7 in e. Add up the possible positions:
11 + 10 + 9 + 8 + 7 = 45 possible combinations
=-)
2006-08-09 14:36:22 · answer #3 · answered by Bill M 2 · 0⤊ 0⤋
If I understand it right, you can get the number of teams by
11!
--------------
(5!)(6!)
which I think will give you 462 teams.
2006-08-09 14:48:45 · answer #4 · answered by dbpygrp 1 · 0⤊ 0⤋
462 different combinations.
the equation is n! / (m! * (n-m)!) = 11! / (5! * 6!) = 462
2006-08-09 14:32:53 · answer #5 · answered by Will 6 · 0⤊ 0⤋
nCr = (n!)/(r!(n - r)!)
11C5 = (11!)/(5!(11 - 5)!)
11C5 = (11!)/(5! * 6!)
ANS : 462 different ways
2006-08-10 02:48:08 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋