2006-08-09 13:24:54 · 21 answers · asked by anna 1 in Science & Mathematics ➔ Mathematics
15
2006-08-09 13:28:38 · answer #1 · answered by Anonymous · 0⤊ 0⤋
3
2006-08-09 13:27:51 · answer #2 · answered by superboredom 6 · 0⤊ 0⤋
15
2006-08-09 13:30:15 · answer #3 · answered by Anonymous · 0⤊ 0⤋
15
2006-08-09 13:30:12 · answer #4 · answered by valoreekayep 1 · 0⤊ 0⤋
15
2006-08-09 13:30:05 · answer #5 · answered by Patrick F 3 · 0⤊ 0⤋
15
2006-08-09 13:29:32 · answer #6 · answered by farudo 2 · 0⤊ 0⤋
Fifteen, OF COURSE, just like the example your teacher gave before assigning that problem.
From the six items A B C D E F you can get
AB AC AD AE AF
BC BD BE BF
CD CE CF
DE DF
EF
5+4+3+2+1=15
2006-08-09 13:33:13 · answer #7 · answered by n4aof 2 · 0⤊ 0⤋
15 example
12
13 23
14 24 34
15 25 35 45
16 26 36 46 56 good brain teaser.
2006-08-09 13:35:02 · answer #8 · answered by Anonymous · 0⤊ 0⤋
If you use a, b, c, d, e, and f as your items, it looks like this:
ab, ac, ad, ae, af,
bc, bd, be, bf,
cd, ce, cf,
de, df,
ef
If you are pairing the items just take the total number(6), subtract 1, and then add the remaining number of items, subtracting 1 each time: 6-1= 5+4+3+2+1=15
2006-08-09 13:49:48 · answer #9 · answered by Bill M 2 · 0⤊ 0⤋
If I understand your question correctly, it's 6 items taken 2 at a time = 6! / (6-2)! = 6!/4! = 30.
[edit]
oops, the above was permutations.
Combinations would be 15.
2006-08-09 13:35:08 · answer #10 · answered by Will 6 · 0⤊ 0⤋