Distribute the minus sign on the second term (you can just drop the minus sign on the first term):
3a+2b-c - 5a + 3c
Now add like terms (those with the same variable)
-2a + 2b + 2c
And that's all you can do unless you are given specific values for a, b, and c.
2006-08-09 11:33:06
·
answer #1
·
answered by just♪wondering 7
·
0⤊
0⤋
First you get rid of the parenthesis and combine like terms. So your equation will look like 3a+2b-c -5a+3c. Notice that the negative of a minus gives you a positive. That is why it is +3c as opposed to -3c.
2006-08-09 11:37:23
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
Group like terms:
3a-5a+2b-c+3c=-2a+2b+2c=2(-a+b+c)
2006-08-09 11:36:42
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
Well, you can't solve it since you didn't list what either is equal to, or if they are equal to each other.
You can, however, simplify it.
(3a+2b-c)-(5a-3c) = 3a+2b-c- 5a + 3c = (3-5)a + 2b + (-1+3)c = -2a + 2b -2c = -2(a+b-c).
But they're right above, you will only learn if you do your own homework.
2006-08-09 11:35:15
·
answer #4
·
answered by Anonymous
·
0⤊
0⤋
(3a+2b-c)-(5a-3c)
=3a+2b-c-5a+3c Distribution
=-2a+2b+2c Arithmetic
=2(-a+b+c) Opposite of Distribution(I forget what that's called)
2006-08-09 11:50:57
·
answer #5
·
answered by Julie 3
·
0⤊
0⤋
(3a + 2b - c) - (5a - 3c)
3a + 2b - c -5a + 3c
clearing parenthesis.When clearing a minus ( - ) sign precedes a parenthesis, the signs inside the parentesis change.
3a - 5a) + 2b (-c + 3c)
colledting like terms
-2a + 2b + 2c
2(-a + b + c)
Extracting the common factor 2
the answer is 2(-a + b + c)
2006-08-09 11:48:35
·
answer #6
·
answered by SAMUEL D 7
·
0⤊
0⤋
Your not solving it. You are SIMPLIFYING IT.
(3a+2b-c)-(5a-3c)
= 3a+2b-c-5a+3c (minus a minus)
= (3a-5a)+2b+(-c+3c) (collect the like terms)
= -2a+2b+2c
= 2(-a+b+c)
2006-08-09 11:33:41
·
answer #7
·
answered by Anonymous
·
0⤊
0⤋
(3a+2b-c) - (5a-3c)
leave (3a+3b-c) and distribute the negative sign to (5a-3c)
so it will be -5a+3c..it's a law of changing the sign..
then change it to addition...
s0 it will be...
3a+2b-c + -5a+0b+3c
so it is equals to..
-2a+2b+2c...
just ask your teacher if this is wrong but i know this is right!
hit me up when u got it aight!..
ric_hamilton_4_3@yahoo.com..
hit me in the messenger when u got time..
2006-08-09 11:36:30
·
answer #8
·
answered by dunker0713 1
·
0⤊
0⤋
(3a + 2b - c) - (5a - 3c)
3a + 2b - c - 5a + 3c
(3 - 5)a + 2b + (-1 + 3)c
-2a + 2b + 2c
2006-08-09 12:04:22
·
answer #9
·
answered by Sherman81 6
·
0⤊
0⤋
Add like terms.
(3a + 2b -c) + (-5a + 3c)
-2a + 2b + 2c
2006-08-09 12:23:14
·
answer #10
·
answered by Ian D 2
·
0⤊
0⤋