2006-08-09 10:32:16 · 7 answers · asked by cocoabundle 1 in Science & Mathematics ➔ Mathematics
nCr = (n!)/(r!(n - r)!)
5C3 = (5!)/(3!(5 - 3)!)
5C3 = (5!)/(3!(2!))
5C3 = (5!)/(6 * 2)
5C3 = (120/12)
5C3 = 10
ANS : 10
2006-08-09 10:39:37 · answer #1 · answered by Sherman81 6 · 0⤊ 0⤋
This is a combination problem. nCr which is a combination of n things taken r at a time...for your problem, a combination of 5 people taken 3 at a time. Even the simplest of scientific calculators will usually have this formula where the probability formulas are. You put the 5 in your calculator, then bring up the formula, then the 3 and it gives you the answer of 10
2006-08-09 18:02:12 · answer #2 · answered by MollyMAM 6 · 0⤊ 0⤋
If 3 people were to be picked, that means 2 are picked to be left off. If Person A were to be left off, there'd be 4 others to join him (B, C, D, and E). If A was on and Person B were to be left off, there'd be 3 choices to join him (C, D, E). If A and B were on and Person C were to be left off, there'd be 2 choices (D & E). And Persons D and E could be left off. 4+3+2+1 = 10. So, 10 possible panels.
2006-08-09 17:59:48 · answer #3 · answered by Kyrix 6 · 0⤊ 0⤋
Probability my man:
5*4*3.
60 Possible panels.
(dangit! your right.... I'm stupid.)
It's 10 abcde
abc
abd
abe
acd
ace
ade
bcd
bce
bde
cde
=10
2006-08-09 17:38:18 · answer #4 · answered by Dallas M 2 · 0⤊ 0⤋
5 choose 3 = 5!/(3!*2!) = 10
2006-08-09 17:40:09 · answer #5 · answered by NordicGuru 3 · 0⤊ 0⤋
And, if your calculator doesn't, then use the formula
nCr = n!/(r!(n-r)!)
like Sherman said.
Doug
2006-08-09 18:09:55 · answer #6 · answered by doug_donaghue 7 · 0⤊ 0⤋
Sherman is right on this one.
2006-08-09 17:42:18 · answer #7 · answered by Incredulous wanderer 2 · 0⤊ 0⤋