2006-08-09 10:30:56 · 12 answers · asked by cocoabundle 1 in Science & Mathematics ➔ Mathematics
A,B,C,D,E
seat 1, five choices
seat 2, four choices (because there has to be one person in the first seat which means they can't be in this one)
seat 3, three choices
seat 4, two choices
seat 5, one choice
So 5*4*3*2*1 = 120 or 5! (5 factorial) = 120
Hope this helps.
2006-08-09 10:39:57 · answer #1 · answered by Anonymous · 0⤊ 0⤋
5 x 4 x 3 x 2 X 1 = 120 ways.
2006-08-09 17:34:28 · answer #2 · answered by Amilucky0707 3 · 0⤊ 0⤋
Simple. Using factorials you can solve this one. 5! = 5 x 4 x 3 x 2 x 1. They can arrange themselves 120 different ways. R U studying for the GRE's?
2006-08-09 17:38:21 · answer #3 · answered by metalman31 2 · 0⤊ 0⤋
Five factorial, or 5 times 4 times 3 times 2 times 1. This is a perfect example of a permutation puzzle.
2006-08-09 17:35:05 · answer #4 · answered by DMBthatsme 5 · 0⤊ 0⤋
25
2006-08-09 17:35:04 · answer #5 · answered by jercha 4 · 0⤊ 0⤋
120
2006-08-09 17:34:09 · answer #6 · answered by jimvalentinojr 6 · 0⤊ 0⤋
5!=120
2006-08-09 17:35:08 · answer #7 · answered by I love to ball 3 · 0⤊ 0⤋
5! (factorial)
5 x 4 x 3 x 2 x 1
120
2006-08-09 17:34:36 · answer #8 · answered by Duds331 5 · 0⤊ 0⤋
5*4*3*2*1=120
2006-08-09 17:34:03 · answer #9 · answered by Heather 4 · 0⤊ 0⤋
This is a permutation because order is important but once a person sits down, the choices keep going down by one so it's 5X4X3X2X1 = 120
2006-08-09 18:07:48 · answer #10 · answered by MollyMAM 6 · 0⤊ 0⤋