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like if i'm 4000m underwater how do you find the water pressure, if air pressure is negligible and with air pressure or a link to somewhere with this info would be helpful as well

2006-08-09 03:50:22 · 0 answers · asked by todd b 1 in Science & Mathematics Physics

0 answers

The formula is P=dgh

where:
P is the fluid pressure;
d is the density of the fluid (the practical density of seawater is about 1025 kg/m3);
g is the acceleration due to gravity (actual value 9.81.. m/s2 and practical value 10 m/s2 );
h is the height of the water column in metres.

Therefore;
P=dgh
P=(1025 kg/m3)(10 m/s2)(4000 m)
P=41,000,000 Pa (Pascal)

2006-08-09 06:55:48 · answer #1 · answered by Anonymous · 0 0

Formula To Find Pressure

2016-10-14 03:00:52 · answer #2 · answered by melville 4 · 0 0

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Whether liberal or conservative, I don't believe that most people understand basic physics--including you. The compressibility of water is irrelevant for the storm surge--water certainly is compressible, but not enough to matter for the storm surge. The storm surge is due to both pressure effects and wind stress on the ocean surface. The wind stress causes the bulk of storm surges. Under normal atmospheric pressure the greatest height that a column of water can be supported by air pressure is about 34 feet. A hurricane might have pressure 10 or 15% less than average, so pressure effects may cause a storm surge of 10 or 15% of 34 feet, so you might get 3 to 5 feet of storm surge from pressure effects alone. However, in strong hurricanes some coastlines might get 25 to 30 feet of storm surge. The extra storm surge comes from the surface wind stress piling water up. Oh, and YES the storm surge is by far the most dangerous aspect of most hurricanes/tropical cyclones. That's what caused at least 6,000 people to die Galveston in the worst natural disaster to hit the US, and that's what caused 500,000 to die in the 1970 cyclone in the Bay of Bengal. EDIT: By the way, here is the definition of storm surge from the IPCC report: "Storm surge The temporary increase, at a particular locality, in the height of the sea dueto extreme meteorological conditions (low atmospheric pressure and/or strong winds). The storm surge is defined as being the excess above the level expected from the tidal variation alone at that time and place." In other words, THEY understand that it is not just the pressure but also the winds that cause the storm surge (and they DON'T mention any of that compressibility nonsense that you bring up). Perhaps if you looked at their reports you might learn some physics. Another EDIT: While I don't like to correct people I agree with philosophically, MTRstudent, Paul B, and VirtualGuy are neglecting the wind's importance in storm surge--that is a mistake. When the wind blows across a water surface, some of the momentum of the wind is transferred to the water surface through viscosity. This drives a current in the direction of the wind that is not that important in the open ocean, but when focused on a beach or a lagoon will push water up the beach, with a return flow at depth. This creates a tilted water surface, higher in the downwind direction with a tangential component of the water weight partially balancing the drag force pushing the water uphill. The actual details are extremely complicated and forecasting storm surge is no easy task, since it depends on so many variables: central pressure, wind speed and direction, where the hurricane goes ashore and bottom topography. This is why it can be so crucial where the eye goes ashore--on one side the wind is pushing water toward shore, on the other side it is pushing water away. AND AN APPROXIMATE FORMULA: If you have a box and there is a wind blowing across it (think of a bay or lagoon), then the change in elevation h at the downwind side of the tank is h = 0.00035*(V^2*L)/H. h is in feet, V is in miles per hour, L is the length of the box in miles, and H is the average water depth in feet. This formula can be found on p148 of "The Divine Wind" by Kerry Emanuel. Emanuel uses an example of a 100 mph wind blowing across 100 miles of water that is 30 feet deep. The formula yields an 11 ft storm surge (without taking pressure into account). Real life is much more complicated than this, but it gives you an idea of how this works.

2016-04-06 23:40:24 · answer #3 · answered by Anonymous · 0 0

first, let's look at your statement. <> and your question. <> ARE YOU SERIOUS? if you're an example, then, at least your segment of the American public doesn't understand basic physics. water doesn't have to compress or expand to create a storm surge. it just has to flow from an area in the ocean where the pressure is relatively high, to an area where the pressure is relatively low. That makes a large area where there's 1-2-3-4 feet of extra water. When that pile of water hits land, more and more follow it. Just like the Indonesia tsunami. In both cases, the extra water piles up as it comes to shallow areas, and eventually spills over the land. You might consider going to some liberal school, and learning some science. Whatever you've been doing up to this point hasn't worked very well. Edit again, from Kendal: <> HUH???? or, <> Maybe the water in the entire ocean isn't being raised? Maybe just where the storm is? Maybe that's why the storm surge doesn't occur all over the coast, but just where the storm comes ashore? Sigh. sad state of physics these days.

2016-03-17 01:50:38 · answer #4 · answered by ? 4 · 0 0

for every 10m the pressure increases 1atm (atmosphere)

so 4000m/10m=400atm increase from sea level this means that total pressure is 401 atm. for psi multiply atm*14.7
so the pressure at 4000m in psi is 401*14.7=5894.7psi

2006-08-09 03:55:07 · answer #5 · answered by nathanael_beal 4 · 0 1

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