A glass marble of density 2.5 x 10^3 kg/m^3 and diameter 5.0 mm is dropped into a cylinder containing cator oil of density 900 kg/m^3. What is the terminal speed of the marble?
2006-08-09 03:39:53 · 4 answers · asked by Lou 1 in Science & Mathematics ➔ Physics
a. 0.022 m/s
b. 2.22 m/s
c. 1.65 m/s
d. 31.5 m/s
2006-08-09 03:52:01 · update #1
i need a little more help than that, this is my first physics class and i dont really understand this stuff
2006-08-09 04:34:51 · update #2
like all other newtonian problems:
1) list all forces at work
(here you have gravity and archimed's buyoncy principle... I guess you can neglect friction since it's kind of dense, a marble. AND because you don't have enough data to compute it...).
2) use the newtonian's n'th law (always forget the right number... it has been a long time, after all)
3) solve the equations.
PS: do the maths yourself. At least, try it and show us what you did. I'm not doing you homework without seeing you try first.
2006-08-09 03:47:33 · answer #1 · answered by Anonymous · 0⤊ 0⤋
1. Measure it's position at some instant of time.
2. What for some time to pass, and note how much time this is.
3. Measure it's position again.
4. Calculate the speed from
v = (Change in position) / (Time)
2006-08-09 13:42:51 · answer #2 · answered by genericman1998 5 · 0⤊ 1⤋
You can't neglect friction. Friction quickly becomes the limiting factor resulting in a terminal velocity of the marble.
2006-08-09 03:49:44 · answer #3 · answered by Blues Man 2 · 0⤊ 1⤋
Stoke's Law
mg - dVg = 6*pi*r*n*v
2006-08-09 03:55:24 · answer #4 · answered by ag_iitkgp 7 · 0⤊ 1⤋