Multiply out to get rid of the brackets, leaving 6-2x=3x+1. Now collect all the terms containing your unknown (x) on the left-hand side, and all the integers on the right-hand side, REMEMBERING TO CHANGE THE SIGNS FOR EACH TERM WHICH CHANGES SIDES. So you get -2x-3x=1-6, i.e. -5x=-5, so x=1.
By the way, Mickey (see above answers), how many years since you passed that algebra exam? Guess it's quite a few!!
2006-08-09 03:25:00
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answer #1
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answered by Anonymous
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1
2006-08-09 01:56:58
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answer #2
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answered by Anonymous
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Q
2(3-x)=3x+1
Solution With Explanation:
2 will b multiply by 3 & -x as thy r in bracket & remaning part will remain the same
so it will be written as
6-2x=3x+1
now what 2 do as they can not b simplyfiy more soo juss put -2x with 3x so -2x will b chg in to +2x & +1 will be transfered to words 6 & +1 will be chg to a -1
it will be written as fellow:
6-1=3x+2x
now u need to simplyfie these sooo here we goo
6-1=5 ,3x+2x=5x
now we have
5=5x
soo we will cancel these by dividing these values
5 divided by 5 gives u 1 soo
ur ans is
x= 1 ANS
ONLY SOLUTION
6-2x=3x+1
6-1=3x+2x
6-1=5 ,3x+2x=5x
5=5x
5/5= x
x=1 ans
i hope u get this sum !
2006-08-09 02:35:28
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answer #3
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answered by Anonymous
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6 - 2x = 3x + 1
6 - 1 = 3x + 2x
5 = 5x
Therefore x = 1
2006-08-12 00:55:09
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answer #4
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answered by Anonymous
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2 (3-x) = 3x + 1
expand the bracket
2 *3 - 2x = 3x +1
6 - 2x =3x +1
subtract 1 from each side
5-2x =3x
add 2x to both sides
5 =5x
divide both sides by 5
5/5 = x
1=x
2006-08-10 04:03:21
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answer #5
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answered by rachael p 2
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2[3-x]=3x+1
6 - 2x = 3x + 1
6 - 1 = 3x + 2x
5 = 5x
x = 1
2006-08-09 02:14:35
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answer #6
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answered by ijlafia2006 2
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2(3-x)=3x+1 1=x
6-2x=3x+1
+2x +2x
6=5x+1
-1 -1
5=5x
divide by 5
2006-08-09 02:00:29
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answer #7
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answered by zidanewolf 1
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2(3-x)=3x+1
6-2x=3x+1
add 6 & 1 = 7
-2x+3 = 1
7+x
2006-08-09 01:59:16
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answer #8
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answered by Anonymous
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2(3-x) = 3x+1
6-2x = 3x + 1
5x = 5
x = 1
2006-08-09 01:56:45
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answer #9
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answered by Anonymous
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x=5
2006-08-09 01:56:04
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answer #10
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answered by David R 3
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