factor the expression x^4 - 13x^2 - 30?

Answer 1

Let y=x^2
Then x^4-13x^2-30=y^2-13y-30
=(y-15)(y+2)
= (x^2-15)(x^2+2)
= (x+sqrt15)(x-sqrt15)(x^2+2)

Answer 2

Let y = x^2

x^4 - 13x^2 - 30
= y^2 - 13y - 30
= (y - 15) (y + 2)
= (x^2 - 15) (x^2 + 2) <-- this could be an acceptable answer
= (x + root(15) ) (x - root(15) ) (x^2 + 2)

Answer 3

Let
y = x²

Thus,
x^4 - 13x² - 30
= y² - 13y - 30
= (y - 15)(y + 2)
= (x² - 15)(x² + 2)
^_^

Answer 4

x^4 - 13x^2 - 30
(x^2 - 15)(x^2 + 2)

Answer 5

There are actual 3 factors of the theory of salvation - previous salvation (the precise element of Christian conversion, i.e. the recent start adventure, Ephesians 2:5, 8; Romans 8:24, Romans 10:13), present salvation (our ongoing salvation adventure by ability of God's protecting skill - Hebrews 2:3; Philippians 2:12; a million Corinthians a million:18), and destiny salvation (the redemption of our bodies and our eternal advantages - Matthew 10:22; Romans 5:9; 2 Timothy 10:13). The time period "get kept", as close to as i am going to tell, replaced into coined contained in the Southern Bible belt. For some reason, that terminology has continuously aggravated me, likely because it sounds unbiblical. I choose the words "born back" and / or "switched over." by the way, Acts 2:38 is the first get at the same time of a real conversion adventure: "Then Peter stated unto them, Repent, and be baptized all and distinctive of you contained in the call of Jesus Christ for the remission of sins, and ye shall receive the present of the Holy Ghost." No different frame of mind to "getting kept" will be found in Scripture. A Scriptural baptism could be carried out "contained in the call of Jesus Christ" (no longer contained in the "titles" Father, Son and Holy Ghost) and repentance and receiving the present of the Holy Ghost are literally not non-obligatory. :-)

Answer 6

PUT x^2=y,
= y^2-13y-30
= y^2-15y+2y-30
= y(y-15)+2(y-15)
=(y+2)(y-15)
=(x^2+2)(x^2-15)
=(x^2+15)(x^2-(sqrt15)^2)
=(x^2+15)(x-sqrt15)(x+sqrt15)

Answer 7

(x^2-15)(x^2+2)

Answer 8

Let x^2=a
so a^2-13a-30
a^2-15a+2a-30=>(a-2)(a-15)
(x^2-2)(x^2-15)

Answer 9

assume m=x^2
so, m^2 - 13m - 30 = (m-15)(m+2) = (x^2-15)(x^2+2)
thats all

Answer 10

same as above