2006-08-08 21:20:12 · 7 answers · asked by stephanie 1 in Science & Mathematics ➔ Mathematics
Do your own homework! This is not hard at all.
2006-08-08 21:23:46 · answer #1 · answered by John R 4 · 1⤊ 0⤋
4x^3 -19x^2 - 5x
= x(4x^2 -19x - 5)
= x(4x+1)(x-5)
thats all
2006-08-09 05:04:32 · answer #2 · answered by balu 1 · 1⤊ 0⤋
= x(4x^2 - 19x - 5)
= x(4x+1)(x-5)
2006-08-09 04:39:46 · answer #3 · answered by Anonymous · 0⤊ 0⤋
4x^3 - 19x^2 - 5x
x(4x^2 - 19x - 5)
x(x - 5)(4x + 1)
2006-08-09 11:15:32 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
x(4x^2-19x-5)
x(4x^2-20x+x-5)
(note. factorize -19x so that product = -20x^2)
x(4x(x-5)+1(x-5)
x(4x+1)(x-5)
answer
2006-08-09 06:14:35 · answer #5 · answered by anuragmaken 3 · 0⤊ 0⤋
wow talk about doin homework
taking it to the next level i guess LOL
2006-08-09 07:43:39 · answer #6 · answered by lia_926 2 · 0⤊ 0⤋
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2006-08-09 04:36:23 · answer #7 · answered by kevin! 5 · 0⤊ 0⤋