Given f(x) = 7 over x - 2, find each value.?

Question

1.) f(3)

2.) f(1.3)

3.) f(2/3)

4.) f(u + 2)

5.) f(2)

Answer 1

all you have to do is substitute x for the value in the bracket.

an example:

f(x) = 7 / (x - 2)
f(3) = 7 / 1 = 7
f(a + b) = 7 / (a + b - 2)

thats all there is to it. now try it yourself. it really isnt too difficult.

Answer 2

if you look at the question you would notice where the xs are
to find the value of the numbers given replace x on the other side of the equal sign in the same way it is replaced in the questions

1.) f(3)=7/3-2
=7/1
=7

2.) f(1.3)=7/1.3-2
=7/-.7
=-10

3.) f(2/3)=7/(2/3-2)
=7/-4/3
=-21/4

4.) f(u+2)=7/(u+2)-2
=7/u ( im not sure about this one)

5.) f(2)=7/2-2
=7/0
=0

Answer 3

5

Answer 4

Given f(x) = 7 over x - 2, find each value.?
1.) f(3)=7/(3-2) =7

2.) f(1.3) = 7/(1.3-2) =7/-0.7 = -10

3.) f(2/3) = 7/(2/3 - 2)=7/(-4/3)= -21/4

4.) f(u + 2)= 7/(u+2-2) =7/u

5.) f(2) = 7/2-2) = 7/0 = Not defined or infinity


4.) f(u + 2)

5.) f(2)

Answer 5

1 f(3) = 7
2 f(1.3) = 7/-0.7=-10
3 f(2/3) = 7/-4/3 = -21/4
4 f(u+2) = 7/u
5 f(2) indefined

Answer 6

1) 7 / (3-2) = 7/1 = 1
2) 7 / (1.3-2) = 7/-.7 = -10
3) 7 / (1/3 - 6/3) = 7/ (-5/3) = -21 / 5
4) 7 / (u+2-2) = 7/u
5) 7 / (2-2) = 7/0 = INFINITY

Answer 7

f(x) = 7/(x - 2)

1.)
f(3) = 7/(3 - 2)
f(3) = 7/1
f(3) = 7

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2.)
f(1.3) = 7/(1.3 - 2)
f(1.3) = 7/(-.7)
f(1.3) = -7/.7
f(1.3) = -7/(7/10)
f(1.3) = (-7/1)/(7/10)
f(1.3) = (-7/1)*(10/7)
f(1.3) = (-70/7)
f(1.3) = -10

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3.)
f(2/3) = 7/((2/3) - 2)
f(2/3) = 7/((2/3) - (6/3))
f(2/3) = 7/((2 - 6)/3)
f(2/3) = 7/(-4/3)
f(2/3) = (7/1)/(-4/3)
f(2/3) = (7/1)*(3/(-4))
f(2/3) = (-21/4)
f(2/3) = -5 1/4

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4.)
f(u + 2) = 7/((u + 2) - 2)
f(u + 2) = 7/(u + 2 - 2)
f(u + 2) = 7/u

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5.)
f(2) = 7/(2 - 2)
f(2) = 7/0
f(2) = Undefined

Answer 8

I agree with the other guy: don't use us for homework.

Anyways,

f(2) is basically x = 2. The f is just -there-. So, 2-2 is 0.

Answer 9

just replace the values:
1) 7
2) -10
3) -21/4
4) 7/u
5) this doesn't exist, unless you consider it from an analytic point of view, case in which it's +/- infinite, but I'm guessing it's for algebra, so it's indefinite

Answer 10

I agree with Lotta, except for #2 should be negative. Also, the proper way to express #5 is "undefined."