B=2,F=3,Z=4
2006-08-08 15:37:09 · 7 answers · asked by demetria_nyree 2 in Science & Mathematics ➔ Mathematics
2t^2 = 3^3/4
2t^2 = 27/4
t^2 = 27/8
t = +/- 0.75*sqrt 6
2006-08-08 16:19:57 · answer #1 · answered by jimbob 6 · 0⤊ 0⤋
substituting in the values gives the equation
2T^2 = 27/4
Dividing both sides by 2 gives T^2 = 27/8
taking the square root of both sides gives
T = 3 root 3 over 2 root 2
multiplying the right side by the name for 1 root 2 over root 2 gives
T = 3 root 6 over 4
2006-08-08 22:43:43 · answer #2 · answered by Bernice 2 · 0⤊ 0⤋
T^2=F^3/BZ=27/8=3.375
T=(3.375)^1/2
2006-08-08 22:44:57 · answer #3 · answered by raj 7 · 0⤊ 0⤋
First, lets solve for T.
BT^2=F^3/Z
T^2=F^3/(ZB)
T = sqrt(F^3/(ZB))
Now lets plug in everything.
F^3 = 27
ZB = 8
T = sqrt(27/8)
T = 1.83711731, or -1.83711731
We have 2 answers for T because of the square root. (T^2 in the initial equation, meaning neg and pos values arrive at the same answer)
2006-08-08 22:45:44 · answer #4 · answered by polloloco.rb67 4 · 0⤊ 0⤋
2(T^2)=(3^3)/4
T^2=27/8
T^2=3.375
T=+1.8371173....or -1.8371173....
2006-08-09 01:57:08 · answer #5 · answered by balu 1 · 0⤊ 0⤋
3*sqrt(3)/ (2*sqrt(2))
2006-08-08 22:43:10 · answer #6 · answered by Anonymous · 0⤊ 0⤋
1.8371 or -1.8371
2006-08-08 22:42:11 · answer #7 · answered by Anonymous · 0⤊ 0⤋