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7 answers

Multiply both sides by the square root of x. The rest is algebra.

2006-08-08 15:16:19 · answer #1 · answered by Dr. Answer 2 · 0 0

Take the log of both sides (it doesn't matter what the base of the logs is). This gets x out of the exponent. Now solve for x. If you take logs to base 1.035, you get a nice compact answer, but not very good for computing.

2006-08-08 22:25:34 · answer #2 · answered by alnitaka 4 · 0 0

multiply both sides by the square root of X

2006-08-08 22:17:47 · answer #3 · answered by Aught 5 · 0 0

(1.035)^x = 2
x = log(1.035)2

or

(1.035)^x = 2
xln(1.035) = ln2
x = (ln2)/(ln(1.035))
x = (ln2)/(ln(207/200))
x = (ln2)/(ln(207) - ln(200))

ANS : x = about 20.14879

2006-08-08 23:29:39 · answer #4 · answered by Sherman81 6 · 0 0

use log.....or scientific calculator...u can get the solution for this question
1.035^x=2
log(1.035^x)=log2
xlog(1.035)=log2
x=log(2)/(log1.035)
x=20.14........................

2006-08-09 05:43:45 · answer #5 · answered by balu 1 · 0 0

Use logarithms.

(1.035)^(X)=2
LN(1.035)^(X)=LN2
XLN(1.035)=LN2
X=LN2/LN1.035= .693/.034=20.15 (rounded)

2006-08-08 22:15:57 · answer #6 · answered by fcas80 7 · 0 0

WTF!

2006-08-08 22:12:16 · answer #7 · answered by courtney 2 · 0 0

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