Multiply both sides by the square root of x. The rest is algebra.
2006-08-08 15:16:19
·
answer #1
·
answered by Dr. Answer 2
·
0⤊
0⤋
Take the log of both sides (it doesn't matter what the base of the logs is). This gets x out of the exponent. Now solve for x. If you take logs to base 1.035, you get a nice compact answer, but not very good for computing.
2006-08-08 22:25:34
·
answer #2
·
answered by alnitaka 4
·
0⤊
0⤋
multiply both sides by the square root of X
2006-08-08 22:17:47
·
answer #3
·
answered by Aught 5
·
0⤊
0⤋
(1.035)^x = 2
x = log(1.035)2
or
(1.035)^x = 2
xln(1.035) = ln2
x = (ln2)/(ln(1.035))
x = (ln2)/(ln(207/200))
x = (ln2)/(ln(207) - ln(200))
ANS : x = about 20.14879
2006-08-08 23:29:39
·
answer #4
·
answered by Sherman81 6
·
0⤊
0⤋
use log.....or scientific calculator...u can get the solution for this question
1.035^x=2
log(1.035^x)=log2
xlog(1.035)=log2
x=log(2)/(log1.035)
x=20.14........................
2006-08-09 05:43:45
·
answer #5
·
answered by balu 1
·
0⤊
0⤋
Use logarithms.
(1.035)^(X)=2
LN(1.035)^(X)=LN2
XLN(1.035)=LN2
X=LN2/LN1.035= .693/.034=20.15 (rounded)
2006-08-08 22:15:57
·
answer #6
·
answered by fcas80 7
·
0⤊
0⤋
WTF!
2006-08-08 22:12:16
·
answer #7
·
answered by courtney 2
·
0⤊
0⤋