The 8 teams will play single elimination afterwards.
2006-08-08 13:50:27 · 4 answers · asked by Beilin Z 1 in Science & Mathematics ➔ Mathematics
4 of the teams are considered stronger than the others, so there are two tiers of teams. Each top tier team should play at most one top tier team. All top tier teams should have similar schedule strength, and all second teams should have similiar schedule strength.
2006-08-08 17:13:37 · update #1
start with 2 legs, then the 2 bottom teams by way of least points/score will have 9/10 position play~off, this way you end up with a final table using same method(not including play~off) to place the rest of the teams. Then all the teams would of played 3 games!
2006-08-08 14:12:00 · answer #1 · answered by Gninja 4 · 0⤊ 0⤋
Yuck - that's not a very good scheduling situation.
Here's a possibility, though I agree that it's not perfectly fair to all teams:
Divide the 10 teams into 1 group of 4 and two groups of 3. The group of 4 will each play round-robin against the other 3 teams, with the last-place team being eliminated. Each team in a group of 3 will play round-robin against the other 2 teams, with the last-place team in each group playing an elimination game against the other.
You could then seed the teams in the single-elimination based on winning percentage in the round robin games, with point/goal differential breaking ties.
2006-08-08 16:39:47 · answer #2 · answered by jimbob 6 · 0⤊ 0⤋
one million. Samoa Joe and Andre the super 2. Jack Swagger and Kurt perspective 3. Scott Steiner and Triple H 4. AJ kinds and Christopher Daniels 5. Jack Evans and Evan Bourne 6. Motor city device weapons 7. Beer money 8. Hardy Boyz
2016-11-04 04:15:07 · answer #3 · answered by Erika 4 · 0⤊ 0⤋
1=2,3,4
2=1,5,6
3=1,7,8
4=1,9,10
5=2,6,7
6=2,5,8
7=3,5,9
9=4,7,10
10=4,8,9
rank by best record assign a tie breaker - heads up, most point or other significant stat. point differential etc.
2006-08-08 14:10:26 · answer #4 · answered by Tim D 4 · 0⤊ 0⤋