Heres the question: The access code for a car's security system consists of four digits. The first digit can't be zero and the last digit must be odd. How many different codes are available?
2006-08-08 12:18:28 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
4500
2006-08-08 13:06:25 · answer #1 · answered by Nobody 3 · 0⤊ 0⤋
9 X 10 X 10 X 5 = 4500
2006-08-08 13:02:33 · answer #2 · answered by MollyMAM 6 · 0⤊ 0⤋
For the first digit there are 9 possibilities: 123456789
For the second and the third digit, there are 10 possibilities: 0123456789
For the fourth digit there are 5 possibilities: 13579
So there are 9*10*10*5 = 4500 possible codes.
2006-08-08 12:27:16 · answer #3 · answered by Anonymous · 0⤊ 0⤋
the first place can be filled in 9 ways (using digits 1 to 9)
second and third places can be filled in 10 ways each (using digits 0 to 9)
The fourth place can be filled in 5 ways (using digits 1,3,5,7,9)
therefore together there are 9*10*10*5 = 4500 different codes
2006-08-08 14:54:55 · answer #4 · answered by qwert 5 · 0⤊ 0⤋
9*10*10*5 = 4500
2006-08-08 13:13:00 · answer #5 · answered by QuietFire 5 · 0⤊ 0⤋
2 days 5 hours- 3000+ Kills
2016-03-27 04:20:53 · answer #6 · answered by Deborah 4 · 0⤊ 0⤋