when you compress air into a tank how much, if any, does the volume of air increase.?

Question

example. 2 tanks equal sizes. tank one has 100 psi. tank 2 has 1000psi. how much more volume of air is in tank 2?

Answer 1

The volume stays the same, based on the size of the container, only the density of air would be different

Answer 2

The volume does not increase in a normal tank. There is an ideal gas law regarding the relationship between temperature, pressure, and volume. There are two ways to compress air: one is to decrease the size of the container, the other is to increase the amount of air in the container. Look up the ideal gas law.

Answer 3

well, it's really the same volume, while it is in the tank! But if you mean, what would the volume be if expelled into the atmosphere (14 psi):

the equation is PV=nRT:

P=pressure, V=volume, n=number of moles, R=a constant, and T=temperture.

R and T don't change. Let V_t be the volume of either tank, V_1 be the volume of the air (at 14psi) from tank 1, and V_2, from tank 2.

Tank 1 gives 100*V_t=n_1RT and Tank 2 gives 1000*V_t=n_2RT.

Thus, n_2 is 10n_1.

14V_1=n_1RT and 14V_2=n_2RT = 10n_1RT, so 1.4V_2=n_1RT = 14V_1, thus V_2=10V_1.

So, Tank 2 gets 10 times the volume of tank 1.

Answer 4

Thinking aloud: The ideal gas law says: PV= NkT, where k is a constant, N is the number of molecules in the tank, P is pressure, V volume, and T is the temperature. So to answer your question, we need to assume that the temperature is the same in both tanks. Since the Volume is the same, we re-write the equation: P/N = kT/V. So set the equations describing the two tanks equal to each other gives: P1/N1 = P2/N2, or P1/P2=N1/N2, so if P2 is 1000psi, and P1 is 100psi, then N2 = 10N1. That means there are ten times the number of molecules in the 1000psi tank.

Answer 5

There is a formula (P*V)/(n*T)
(Pressure*Volume)(number of molecules*Temperature) For normal conditions, this value stays the same. If one variable changes, one or more of the other variables will change.
(P1*V1)/(n1*T1) = (P2*V2)/(n2*T2)

Since both tanks are the same size and I am going to assume they are at the same temperature. The fomula becomes
P1/n1 = P2/n2

100psi/n1 =1000psi/n2
solve for n2
n2 = 10*n1
So tank2 has 10 times more air molecules than tank1.

Answer 6

Ten times as much, if the final measurement is taken at standard temperature and pressure. Because of forces such as van der Waals, air is not exactly a perfect gas so the actual result will be slightly different.

Answer 7

For every 14.7psi, you get another tankful of air...
1000 - 100 = 900psi
900psi / 14/7 = 61.22 tankfuls more..