English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

how to convert j notation to phasors and vice versa?

2006-08-08 06:11:51 · 6 answers · asked by devil_4k 2 in Science & Mathematics Mathematics

6 answers

just imagine a grid and the y axis is ur imaginary number while ur x axis is the real part. Graph out ur line using ur x and y values and use simple trig to figure out the angle and length of the line "

IE: 5+4j

line goes from (0,0) to (5,4)

Work backwards if u want to do the opposite.

2006-08-08 06:46:57 · answer #1 · answered by Ak2ng 3 · 0 0

This Site Might Help You.

RE:
how to convert j notation to phasors and vice versa?
how to convert j notation to phasors and vice versa?

2015-08-18 14:48:06 · answer #2 · answered by Drea 1 · 0 0

I'm not sure what you mean by 'phasors' (unless your a Trekkie junkie )

I'm guessing that you mean a vector in polar coordinate notation (r,Θ). If that's the case, then to convert a vector from a complex number (a + jb) use

r = √(a² + b²)
Θ = arctan(b/a)

Remember that if a is negative, you have to add 180° (or π radians) to the answer your calculator gives you for arctan.

To go from polar to rectangular notation, use

a = r*cos(Φ)
b = r*sin(Φ)

and get

a + j*b


Doug

2006-08-08 06:44:37 · answer #3 · answered by doug_donaghue 7 · 1 1

The formula for converting farenheit to celsius is c=5/9*(f-32). The formula for converting celsius to farenheit is f=c*(9/5)+32

2016-03-16 22:21:02 · answer #4 · answered by Anonymous · 0 0

Mark G is correct
Mail me at jrc_skyexpress@yahoo.co.uk and Í'send you some VB5 code (similar to C) to do all the transforms for you, in any direction.

2006-08-09 23:32:24 · answer #5 · answered by just "JR" 7 · 0 1

yes, all it is, as long as you stick to LTI (linear time-invariant) systems with no harmonic content.

It's just like switching form x,y (z) format to polar (cylindrical) format.

2006-08-08 06:44:42 · answer #6 · answered by kmclean48 3 · 0 0

complex numbers rectangular to polar conversion,

a+jb .................. r/O

r= root a^2+b^2
O=(angle) Tan-1 b/a

other way

a=r cos O
b=r sin O

2006-08-08 06:38:51 · answer #7 · answered by Mark G 2 · 0 0

i dont know

2006-08-08 06:17:03 · answer #8 · answered by Anonymous · 0 3

fedest.com, questions and answers