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M varies directly as the square of V. When V=4, M=24. WHat is the value of M when V=6? and please show ALL steps.

2006-08-08 04:17:37 · 4 answers · asked by blazingwolf7 1 in Science & Mathematics Mathematics

4 answers

If M varies directly as v² then

M = kV²

for some k

in this case

24 = k(4)² = k*16

so k = 1.5

Now it's just 'plug 'n play

M = 1.5*6² = 1.5*36 = 54


Doug

2006-08-08 04:29:18 · answer #1 · answered by doug_donaghue 7 · 0 0

M = kV^2

24 = k * 4^2
24 = 16k
k = (24/16)
k = (3/2)

M = (3/2)(6^2)
M = (3/2)(36)
M = 3 * 18
M = 54

2006-08-08 12:14:09 · answer #2 · answered by Sherman81 6 · 0 0

v=4: M=24
it can be wriiten as v=x;m=x^2+2*x
therfore when v=6; M=6^2+2*6=48

2006-08-08 11:25:26 · answer #3 · answered by sajesh.k 2 · 0 0

(k= constant):
M = k v ^2
Plug it in!:
24 = k * 4^2
Simplify:
24 = k * 16
commutative:
k = 1.5
Put it in equation:
M = 1.5 v ^2
Check:
24 = 1.5 * 4^2
Correct : )

2006-08-08 11:31:38 · answer #4 · answered by flit 4 · 0 0

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