Replace the letters 'c'and'd' in 28c9d by numbers so that the five digit is divisible by 36?

Answer 1

28296
c is 2
d is 6

Can also be 28692
c is 6
d is 2

Answer 2

c= 6, d=2, or c=2, d=6


Basically, you know that c+d = 8
That is because 2+8+c+9+d = a number divisible by 9 (That is one of the properties of numbers divisible by 9, the digits will add up to a number divisible by 9) Since 36 is a multiple of 9 (9x4), that property is also true for numbers divisible by 36.

One of the properties of numbers divisible by 4 is that the last 2 digits will be divisible by 4. Again, since 36 is a multiple of 4 (4x9), that property will also be true for numbers divisible by 36. So that means that d can only be 2 or 6.

You also know that d must be an even number, because 36 is a multiple of 2 (2x18) so the property of only even numbers being divisible by 2 will be true.

When you plug 2 in as d, c must equal 6, which does work. When you plug 6 in as c, d must equal 2, which also works.

There may be other solutions as well, but those are the first ones I can think of

Answer 3

Since 36 is even, 28c9d must be, so d can only be 0,2,4,6, or 8. Since 36 is divisible by 4, the last TWO digits of 28c9d must also be, so d can only be 2 or 6. And since 36 is divisible by 9, the digits of 28c9d must add up to a multiple of 9 {look up the method of casting out 9's as a way of checking arithmetic}. Since the 2, 8, and 9 add up to 19, the c and d must add up to 8, making a digit sum of 27.

So your solutions are 28296 or 28692.

Answer 4

C will equal 6 and D will equal 2

28692 / 36 = 797

Answer 5

Two answers possible:

28296 = 36*786
28692 = 36*797

Answer 6

28296 and 28692

Answer 7

28296 and 28692

Answer 8

28296