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how much would a bucket of neutrons weigh....approximate answer

2006-08-08 03:05:06 · 25 answers · asked by Ariel 2 in Science & Mathematics Physics

many funny answers coming in....the volume is immaterial as i said "approximate"
you could assume the volume. anyways keep the volume as m^3. if u knew the density of neutrons u would be surprised at the weight of a bucket of neutrons.


and for those who say it would be very very light are weigh nothin...u know noting in physics

2006-08-08 03:14:37 · update #1

pls note: imeant .5 m^3 above

2006-08-08 03:15:16 · update #2

clue:the density of neutrons is very very high...so the weight is obviously goin to be high

2006-08-08 03:25:29 · update #3

25 answers

A typical neutron has a mass of 1.675 x 10 ‾27kg and a classic volume of 5.6 x 10 ‾45m³

The density therefore equals (1.675 x 10 ‾27)kg divided by (5.6 x 10 ‾45)m³ which equals 2.857 x 10^17 kg/m³.

If the bucket had a capacity of say 10 litres (typical household bucket) then it has a volume of 0.01m³.

To work out the mass of the neutrons required to fill the bucket we need to multiply the density by the volume...

2.857 x 10^17 kg/m³ x 0.01m³ = 2.857 x 10^15 kg

Or 2,857,000,000,000,000kg.

This has worked out to be remarkably close to the mass of a neutron star which is as between 2 and 3 x 10^26 kg/km³.

2006-08-08 03:35:29 · answer #1 · answered by Trevor 7 · 1 0

Degenerate matter
From Wikipedia, the free encyclopedia

Degenerate matter is matter which has sufficiently high density that the dominant contribution to its pressure arises from the Pauli exclusion principle. The pressure maintained by a body of degenerate matter is called the degeneracy pressure, and arises because the Pauli principle forbids the constituent particles from occupying identical quantum states. Therefore, reducing the volume requires forcing the particles into higher-energy quantum states. The species of fermion are sometimes identified, so that we may speak of electron degeneracy pressure, neutron degeneracy pressure, and so forth.

Imagine that there is a plasma, and it is cooled and compressed repeatedly. Eventually, we will not be able to compress the plasma any further, because the Exclusion Principle states that two particles cannot be in the exact same place at the exact same time. When in this state, since there is no extra space for any molecules, we can also say that the molecule's momentum (or location) is extremely defined. Therefore, if uncertainty in momentum * uncertainty in energy = Planck's Constant, then we must say that their energy is extremely uncertain. Therefore, even though the plasma is cold, the molecules must be moving very fast on average. This leads to the conclusion that if you want to compress an object to a very small space, you must use tremendous force to control their momentum.

Unlike a classical ideal gas, whose pressure is proportional to its temperature (P = nkT, where P is pressure, n is particles per unit volume, k is Boltzmann's constant, and T is temperature), the pressure exerted by degenerate matter depends only weakly on its temperature. In particular, the pressure remains nonzero even at absolute zero temperature. At relatively low densities, the pressure of a fully degenerate gas is given by P = Kn5 / 3, where K depends on the properties of the particles making up the gas. At very high densities, where most of the particles are forced into quantum states with relativistic energies, the pressure is given by P = K'n4 / 3, where K' again depends on the properties of the particles making up the gas.

Note that degenerate matter still has normal thermal pressure, but at high densities the degeneracy pressure dominates. Thus, increasing the temperature of degenerate matter has a minor effect on total pressure until the temperature rises so high that thermal pressure again dominates total pressure.

You do the math.

2006-08-08 03:37:07 · answer #2 · answered by kanajlo 5 · 0 0

A neutron wigths 1.6E-27 kg, and has a radius of 1E-16 m.

I will assume your bucket is a 10 l one (which is about the usual),
so there is room in it for about 1.3E45 (I am assuming there are some gaps between them, just like between marbles). Multiplied by the mass, you get 2E18 kg, or 2E15 tonnes. That is the weight of a cube of water that would be 126 km wide.

Just don't drop the bucket, as it would fall right through the planet.

2006-08-08 03:09:28 · answer #3 · answered by Vincent G 7 · 1 0

The mass of a neutron is 1,6749 x 10^(-27) kg... of course, you've failed to specify the size of the bucket or the number of neutrons to consider.

I've read your edits... You are talking about the remanants of a neutron star? This material is very dense because it was once in a star.... I did not assume that you meant neutron star mass and just a bucket of neutrons like you said.

2006-08-08 03:19:37 · answer #4 · answered by hyperhealer3 4 · 0 0

The number of neutrons would depend not only on the volume of the container, but also on temperature and barometric pressure.

2006-08-08 04:11:05 · answer #5 · answered by Kevin H 7 · 0 0

i read it somewhere that a body sized of a small pea consisting of only neutrons would weigh approx 10000 tonnes. and suppose that a pea is 30/1000000 of the weight of bucket. so the answer woulf be 300,000,000,000 tonnes

2006-08-08 03:25:32 · answer #6 · answered by karan tripathi 2 · 0 0

What is the volume of the bucket?

2006-08-08 03:11:12 · answer #7 · answered by shawnabobonna 4 · 0 0

You would have to specify the size of the bucket at least.
This is not something to think about. Just dumb.

2006-08-08 03:08:44 · answer #8 · answered by Texas Cowboy 7 · 0 0

Approximately the weight of a giant yawn.

2006-08-08 03:09:12 · answer #9 · answered by MissSubversive 3 · 0 0

Depends on the size of the bucket & what plane of existance you were on....

2006-08-08 03:13:07 · answer #10 · answered by fairly smart 7 · 0 0

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