19=3e^2x
full detailed answer cheers
2006-08-08 02:07:47 · 21 answers · asked by devil_4k 2 in Science & Mathematics ➔ Mathematics
Remember, to get rid of the 'e', take log to the base 'e' (ln) of both sides.
(1/2) * ln(19/3) = x
2006-08-08 02:16:20 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Use rule of exponents and logs:
ln (e^x) = x * ln (e) = x * 1 = x
19=3e^2x
(19/3) = e^2x
ln (19/3) = ln (e^2x)
ln (19/3) = 2x * ln (e)
ln (19/3) = 2x * 1
x = [ln (19/3)] / 2
=ln [ (19/3)^(1/2)]
2006-08-08 13:22:03 · answer #2 · answered by Anonymous · 0⤊ 0⤋
19 = 3e^2x
(19/3) = e^2x
Log(19/3) = 2x
x= (Log(19/3))/2
2006-08-08 02:17:42 · answer #3 · answered by •NaNNou• 2 · 0⤊ 0⤋
19 = 3e^2x
19/3 = e^2x
ln (19/3) = 2x
x = [ln (19/3)]/2
x = 0.9229....
2006-08-08 02:17:09 · answer #4 · answered by maya_crunk 3 · 0⤊ 0⤋
Surely you can do at least the first step? As per any equation, do the same thing to both sides until you've isolated x. Let us know what step you're stuck on.
2006-08-08 02:13:16 · answer #5 · answered by kheserthorpe 7 · 0⤊ 0⤋
e^2x = 19/3
Natural log both side:
2x = Ln (19/3)
x = (1/2) * [ Ln (19/3) ]
x = 0.923
2006-08-10 17:30:51 · answer #6 · answered by AJ 2 · 0⤊ 0⤋
1) divide by 3 .... e^2x = 19/3
2) take nat log ln(e^2x) = ln (19/3)
3) solve ... 2x = 1.845826
x = .9229
3 * e^2(.9229) = 19
2006-08-08 02:53:19 · answer #7 · answered by Brian D 5 · 0⤊ 0⤋
I'm sorry but what does the little simbol between the e and the 2 mean?
2006-08-08 02:12:24 · answer #8 · answered by Linda 3 · 0⤊ 0⤋
you can work that out with logarithms, I got rid of my log tables book when I left school.
I hate logarithms.
I bet you have never had to look at a logarithms book.
I have got the shakes just thinking about that book.
2006-08-08 02:13:59 · answer #9 · answered by Anonymous · 0⤊ 0⤋
log(19/3) = 2x
x = log(19/3) / 2
2006-08-08 02:11:20 · answer #10 · answered by Larry 6 · 0⤊ 0⤋