How can i can rewrite (x^2+3x-4)/(x^2-2x-8) as 1 + (5x+4)/(x^2-2x-8).Please explain me.
2006-08-07 23:30:00 · 6 answers · asked by star123 2 in Science & Mathematics ➔ Mathematics
Nagpapatawa ba kayo?
(x^2 + 3x - 4) / (x^2 - 2x - 8)
= (x^2 - 2x + 5x - 8 + 4) / (x^2 - 2x - 8)
= [(x^2 - 2x - 8) + (5x + 4)] / (x^2 - 2x - 8)
= (x^2 - 2x - 8) / (x^2 - 2x - 8) + (5x + 4) / (x^2 - 2x - 8)
= 1 + (5x + 4) / (x^2 - 2x - 8)
2006-08-07 23:50:58 · answer #1 · answered by Joe Mkt 3 · 4⤊ 0⤋
the key is to do by long division. the numerator is x^2+3x-4 and the denominator is x^2-2x-8. the way to do it is similar to the normal numerical division. First you ordered the polynomial in the order of decreasing power. then proceed to do the division. Another way is to write x^2+3x-4=x^2+(5x-2x)+(4-8)=(x^2-2x-8)+5x+4. It should be clear that when the division is taken the answer is as above
2006-08-07 23:41:27 · answer #2 · answered by carl yap 1 · 1⤊ 0⤋
YES.
1 + ((5X + 4)/(x^2 - 2x - 8))
= ((x^2 - 2x - 8)/(x^2 - 2x - 8)) + ((5X + 4)/(x^2 - 2x - 8))
= ((x^2 - 2x - 8) + (5X + 4))/(x^2 - 2x - 8)
= (x^2 - 2x - 8 + 5x + 4)/(x^2 - 2x - 8)
= (x^2 + 3x - 4)/(x^2 - 2x - 8)
2006-08-07 23:40:29 · answer #3 · answered by Anonymous · 1⤊ 0⤋
Two words: Synthetic Division
Go back to your text book and learn how to do synthetic division of polynomials. It's very similar to doing long division in arithmetic (in fact, it's a more generalized form of the long division algorithm)
Doug
2006-08-07 23:41:45 · answer #4 · answered by doug_donaghue 7 · 0⤊ 0⤋
Perhaps you may want to start rewriting your grammar before throwing yourself in the e=mc2 cockpit. It's elemental and detrimental.
2006-08-07 23:35:05 · answer #5 · answered by Gotta Lotta Nerve 3 · 0⤊ 1⤋
you cannot
2006-08-07 23:32:24 · answer #6 · answered by doubleas_an_2010 1 · 0⤊ 1⤋