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i need to prepare in my lab 50mM triethanolamine buffer, if any body knows plz let me know

2006-08-07 21:46:55 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

4 answers

How much volume? What pH? What buffer (Triethanolamine-HCl, Triethanolamine-acetate or other)?
If you have pure base then the MW=149.2
For preparing V ml of solution you need:

mass=mole*MW= C*V*(10^-3)*MW =
=0.05*V*10^-3*149.2 gr

Take a suitable volumetric cylinder, put some water in it, dissolve the quantity of base you calculated, add drops of the appropriate acid until you reach the desired pH (always stirring and following the pH with a pH-meter). Add water up to V ml and you're done.

If you want large quantities you can make a more concentrated solution (10x, that is 0.5 M) and dilute from that.

2006-08-07 23:23:25 · answer #1 · answered by bellerophon 6 · 0 0

Triethanolamine Buffer

2016-10-31 23:39:44 · answer #2 · answered by ? 4 · 0 0

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RE:
preparation of 50mM triethanolamine buffer?
i need to prepare in my lab 50mM triethanolamine buffer, if any body knows plz let me know

2015-08-18 05:44:43 · answer #3 · answered by ? 1 · 0 0

The only true buffer is 0.025M quantities of KH2PO4 & Na2HPO4 which gives pH of 6.88 @ 20ºC. The other pHs aren't in the true buffer region but can be made by either adding phosphoric acid to lower or sodium hydroxide to raise the pH using a previously calibrated pH meter.

2016-03-15 04:55:07 · answer #4 · answered by Anonymous · 0 0

if you have pure trieth.. find the molecular weight and put the M.W /0.05 in one litre empty bottle.then full it with water and you have 50mM concetration

2006-08-07 21:55:25 · answer #5 · answered by michael 1 · 0 0

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