What is the answer to the math problem Hocus+Pocus=Presto?

Question

It uses the number 0-9.
You can only use the numbers one time for each letter.

Answer 1

..HOCUS
+POCUS
--------------
PRESTO

C=8 E=5 H=9 O=2 P=1 R=0 S=6 T=7 U=3

..92836
+12836
-----------
105672

This is the only solution

Answer 2

Hocus Pocus Presto

Answer 3

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I think I have a simple proof of its impossibility. E = even, O = odd There are 3 possible types of equation: E ± E = E E ± O = O O ± O = E Note there is no equation containing exactly 2 Es. We are given 4 Es and 5 Os. How do we place the 4 Es? I claim it's impossible to put 4 Es in the pattern without requiring that a 5th E be added. That is, 1. If you put 3 Es such that they all are in different rows and columns (e.g., on a diagonal), adding the 4th will result in a row and a column, each with 2 Es and thus requiring another, making at least 6. 2. If you put 2 Es in the same row or column (r/c), you must put the 3rd E in that r/c. Adding the 4th will produce another r/c with 2 Es, requiring a 5th. 3. And obviously if you put 3 Es in the same r/c, adding the 4th will also require a 5th. If sfguybryan shows his solution with two 6s he'll blow my argument out of the water.