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How can i convert (x^2+3x-4)/(x^2-2x-8) to proper fraction?

2006-08-07 16:42:41 · 3 answers · asked by star123 2 in Science & Mathematics Mathematics

3 answers

Use synthetic division.

1 + (5x + 4)/(x^2 -2x - 8)

2006-08-07 17:53:15 · answer #1 · answered by Michael M 6 · 3 3

In this context, I'm not sure what you mean by proper fraction.
x^2+3x-4 and x^2-2x-8 share no common factors, but you can rewrite it as 1 + (5x+4)/(x^2-2x-8)

2006-08-07 23:54:25 · answer #2 · answered by MsMath 7 · 0 0

when you factor both top and bottom, u find that the top is....(x+4)(x-1)...and the bottom is...(x-4)(x+2) therefore. it is already in lowest terms and proper.

2006-08-07 23:52:43 · answer #3 · answered by who be boo? 5 · 0 0

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