yes or no
2006-08-07 15:23:09 · 13 answers · asked by Anonymous in Science & Mathematics ➔ Physics
To float, you need to displace the weight of air equal to your weight and the weight of your equipment.
I doubt you'd need 600 tons of helium. I bet 20 or 30 pounds would do the trick.
2006-08-07 15:28:44 · answer #1 · answered by Wicked Mickey 4 · 0⤊ 1⤋
Yes, if the suit is allowed to expand like a balloon, you will float, provided it is reasonably light weight and strong enough to hold the pressure.
You could float with a lot less helium. One guy tied a bunch of helium balloons to a lawn chair and floated over L.A. He used a b.b. gun to pop a few balloons so that he would land.
2006-08-07 15:32:12 · answer #2 · answered by Bernard B 3 · 0⤊ 0⤋
Are there even 600 tons of Helium available on the whole planet?
2006-08-07 15:26:48 · answer #3 · answered by Pseudo Obscure 6 · 0⤊ 0⤋
Well, if you breath all that helium , you, your offsprings and so on so forth for the rest of eternity, will have a very high pitched voice
LOL
2006-08-07 15:34:15 · answer #4 · answered by trebornerd 1 · 0⤊ 0⤋
600 ton? lol, that's gonna be a big suit, but yes, most definitely...
2006-08-07 15:26:58 · answer #5 · answered by rei 3 · 0⤊ 0⤋
depending on how big the suit is. If you compress the air too much, it will not float at all.
2006-08-07 15:33:25 · answer #6 · answered by 2feEThigh 5 · 0⤊ 0⤋
500 tons of helium would be about the size of the moon?
2016-03-27 03:06:05 · answer #7 · answered by Geraldine 4 · 0⤊ 0⤋
Really big suit!Yes.
2006-08-07 15:26:57 · answer #8 · answered by Wounded duckmate 6 · 0⤊ 0⤋
no ur suit will blast
it could not stand that high of pressure
2006-08-07 15:26:46 · answer #9 · answered by arifin ceper 4 · 0⤊ 0⤋
I don't care, please stop spamming the boards with useless junk! You've been reported, repeatedly... Seriously post ONE QUESTION at a time, not 3-5 of the SAME DAMN QUESTION. Stop cluttering the boards, please?
Same junk, different day, apparently...
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2006-08-08 05:35:38 · answer #10 · answered by Michael Gmirkin 3 · 0⤊ 0⤋