2006-08-07 12:23:09 · 37 answers · asked by SQRD 2 in Beauty & Style ➔ Other - Beauty & Style
NOPE!!
2006-08-08 03:06:51 · answer #1 · answered by ♥Stranger In Maine™♥ (Thriller) 7 · 0⤊ 0⤋
Since Shakira is ugly and looks like a man, yes there definitely is.
2006-08-07 12:26:21 · answer #2 · answered by * 5 · 0⤊ 0⤋
Hotness is in the eye of the beholder. For me, the answer is no. Frankly I'd say that she's hotter since she's adopted a more au naturale look than her blonde Laundry Service phase.
2006-08-08 13:34:10 · answer #3 · answered by dick_coxnbutz 2 · 0⤊ 0⤋
I place Shakira, Jessica Simpson, and Jessica Alba all in the same category. They are all 10's.
2006-08-07 12:27:56 · answer #4 · answered by Joseph L 4 · 0⤊ 0⤋
What do you think she spends a month on waxing? I bet she goes through some dough. Definitely a lot hotter women out there.
2006-08-07 12:28:26 · answer #5 · answered by daspook19 4 · 0⤊ 0⤋
What a dumb waste of 5 points! Of course there is hotter women besides her. She is not that hot and she realy needs a hair cut. She is not ugly but she is not to hot.
2006-08-07 12:29:50 · answer #6 · answered by Tess D 1 · 0⤊ 0⤋
No one can move like Shakira. She makes every motion seductive. She might not be human because it just wouldn't be fair if I had to compete with her.
2006-08-07 12:27:18 · answer #7 · answered by theinfalliblenena 4 · 0⤊ 0⤋
She's beautiful and I like the way she moves, but there's something about the way she sings (all pretty-like til she pronounces a word or ten with a weird honk-like noise in the back of her throat) that reminds me of Bobcat Goldthwait or Pee-Wee Herman. That ruins her for me.
2006-08-07 12:29:56 · answer #8 · answered by ? 5 · 0⤊ 0⤋
Uh...yeah. Shakira is not all that. She isn't even in my top 100.
2006-08-07 12:27:00 · answer #9 · answered by El Teke 4 · 0⤊ 0⤋
There is always one woman hotter than the other.
2006-08-07 12:27:01 · answer #10 · answered by Anonymous · 0⤊ 0⤋
I agree with Ness. Shakira is Fugly!
2006-08-07 12:26:54 · answer #11 · answered by Anonymous · 0⤊ 0⤋