Volume of a sphere is 4(pi)r^3/2.
4(3.14)3^3
= 12.64(27)
= 341.28 divide by 2, since the shape is a hemisphere.
= (so it comes out as) [170.64 sq. cm] (only an estimate, since the diameter is about, and 3.14 is only a rounded decimal.)
For Surface Area of the curved part, just take the Surface Area as if it were the whole sphere, then divide it by 2.
Surface Area of a Sphere is 4(pi)r^2.
4(3.14)3^2
=12.64(3)^2
=12.64(9)
=113.76 (divide in half again, since its Surface Area of a hemisphere and not a sphere)
113.76/2= 56.88cm (also an estimate, for the reason above from the last problem.)
2006-08-07 11:41:10
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answer #1
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answered by Anonymous
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Volume of a sphere formula
v= 4/3 π r³
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caculating volume of a sphere Method 1
v = 4/3 π r
4/3 = 1.333333333
v =1.333333333(3.141592654)3³
v =1.333333333(3.141592654(27)
v = 4.188790204(27)
Multiplying 1.333333333 times 3.141592654=4.188790204
v = 113.0973355
v = 113.09 cm
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caculating volume of a sphere Method 2
v= 4/3 π r³
v = 4/3(3.141592654)(3³)
v = 4/3(3.141592654)(27)/3
3 x 3 x 3 = 27
v = 12.56637061(27)/3
Multiplying 4 times 3.141592654 = 12.56637061
v = 339.2920066/3
v = 113.0973355
v = 113.09 cm rounded to two decimal places
The answer is 113.09 cm
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Solving for the surface area of a sphere
Formula
s = 4 π r²
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s = 4(3.141592654)(3²)
S = 4(3.141592654(9)
3² = 9 or 3 x 3x 3 = 9
s= 12.56637061(9)
Multiplying 4 times 3.141592654 equals 12.56637061
s = 133.0973355cm
s = 113.09 cm rounded to two decimal places
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It appears that the volume and the surface area of a sphere are the same.
2006-08-08 05:31:50
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answer #2
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answered by SAMUEL D 7
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Given diameter D = radius(R)/2 if Sphere quantity = 4/3(pi)r^3 in case you substitute r for 2r ( because of fact it doubled. ) it provides you with a quantity 8 cases larger than the previous. if sphere floor section = 4(pi)r^2. substitute r for 2r. it provides you with a floor section 4 cases larger than previous,. :D
2016-11-04 02:17:08
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answer #3
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answered by ? 4
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HAHAHAHAHAHA A hemispherical sphere, that's great!
2006-08-07 11:30:21
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answer #4
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answered by Anonymous
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