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3 answers

Watsons Lemma has to do with the relationship between the behavior of a function in the neighborhood of the origin and the behavior of its Laplace transform

If

f(t) < Me^(at)

and if, in some neighborhood of t=0 the function f(t) has a Maclaurin polynomial expansion given as

sum (cr*t^r)/(r!)

where r runs from 0 to ∞ (and the cr are the Maclaurin coefficients of the polynomial expansion) then the LaPlace transform of f(t) has an asymptotic expansion of the form

F(z) ≈ sum cr*z^(-r-1)

as r runs from 0 to ∞

It's really just a generalization of the Tauberian theorems.


Doug

2006-08-07 13:15:28 · answer #1 · answered by doug_donaghue 7 · 1 0

Here is your answer to what...

Coherent, systematic coverage of standard methods: integration by parts, Watson s lemma, LaPlace s method, stationary phase and steepest descents. Also treated are the Mellin transform method and less elementary aspects of the method of steepest descents.

2006-08-07 16:55:12 · answer #2 · answered by tribal3fx 2 · 0 0

http://math.arizona.edu/~lega/583/Spring99/lectnotes/AE2.html

2006-08-07 20:14:42 · answer #3 · answered by kain2396 3 · 0 0

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