balanced net ionic equations?

Question

(a)NaC2H3O2(aq) + HCl(aq) ->
(b)ZnS(s0 + HBr(aq) ->
(c)KCl(aq) + Hg2(NO3)2(aq) ->
(d)Ni(NO3)2(aq) + CuSO4(aq) ->
(e)Li(s) + H2O(l) ->
(f)H2SO4(aq) + KOH(aq) ->
(g)HC2H3O2(aq) + NaOH(aq) ->

if someone could please help me with any of these, i would greatly appreciate it! i don't understand them at all.

Answer 1

a) CH3COONa(aq) + HCL(aq) --> CH3COOH + NaCl
b)ZnS + 2HBr --> ZnBr2 + H2S
c) 2KCl + Hg2(NO3)2 --> 2KNO3 + Hg2Cl2
d) Ni(NO3)2 + CuSO4 --> NiSO4 + Cu(NO3)2
e) Li + H20 --> Li(OH)3 ---> not sure... its either this or the next one
e) 2Li + 3H20 --> 2 LiH3 + 3O2 (i think its this one)
f)H2SO4 + 2KOH --> K2SO4 + 2H20
g) CH3COOH + NaOH --> CH3COONa + H2O


hey if you liked the answer and if i am ryt, please let me know,,, would appreciate it!..thanks..

Answer 2

I'm not exactly sure what you need to be doing, but here I think this is right....

1) I don't know what the structure of NaC2H3O2 looks like, so I can't help you there

2) ZnS + 2HBr -> Zn(Br2) + H2S this is because S has a net -2 charge, and Zn has +2 and the H has a +1 and Br -1, so you must double the HBr to make it work out.

3) 2KCl + Hg2(NO3)2 -> 2K(NO3) + 2HgCl because K is +1, Cl -1, and NO3 -1 (I believe) and so Hg must be +1... so you have to double the KCl since there are 2 Hgs and 2 NO3s. This one is the one I am least sure of.

4) Ni(NO3)2 + CuSO4 -> NiSO4 + Cu(NO3)2 since Ni and Cu are both +2, NO3 is -1 but there are two of them already, and SO4 is -2, but only one is needed to counteract the Ni.

5) 2Li + H2O = Li2O + H2(g) I'm not totally sure if this is a viable reaction, but... it works out in terms of the net ionic charges since Li and H are both +1, and O is -2.

6) H2SO4 + 2KOH -> K2SO4 + 2H2O since H is +1 and SO4 is -2 and K is +1 and OH is -1, so you have to double the KOH to match the 2 Hs and 1 SO4's charges

7) I don't know what the compound HC2H3O2 looks like. If you could name it using IUPAC nomenclature I might be able to help you... if you know how to do that, you would have learned it in organic chemistry most likely... sorry.