Helgas computer cost $100 less than 3 times what her printer cost. If the total was$1100, How much did each item cost.
2006-08-07 08:29:11 · 5 answers · asked by Phoenix 1 in Education & Reference ➔ Homework Help
c = 3p -100
p +c = 1100
p + 3p -100 = 1100
4p = 1200
p= 300, so printer= $300
c= 800, so computer = $800
2006-08-07 08:37:22 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The printer costs $300. The computer costs $800
If the printer costs $300, then 3 times that is $900. If the computer costs $100 less than that, then it is $800
2006-08-07 15:37:33 · answer #2 · answered by alicia9562 2 · 0⤊ 0⤋
x - 100 = 3 y, so x = 3y + 100
x + y = 1100, so 3y + 100 + y = 1100, so 4y + 100 = 1100, so 4y = 1000, so y = 250, so x = 3y + 100 = 850
2006-08-07 15:34:07 · answer #3 · answered by Larry 6 · 0⤊ 0⤋
P+C = 1100.
C = 3*P-100
P + 3*P-100 = 1100
4*P -100 = 1100
4*P = 1200
P = 300
C = 800
2006-08-07 15:33:41 · answer #4 · answered by Ranto 7 · 0⤊ 0⤋
P+C=1100
C=3P-100
plug in 3P-100 into first equation:
P+3P-100=1100
4P-100=1100
4P=1200
P=300 then plug this into either first equation to get computer's cost:
c+300=1100
c=800
2006-08-07 19:00:57 · answer #5 · answered by Maya F 1 · 0⤊ 0⤋