Last weekend mary worked 5 hoursmore than her assistant mac. If they both worked a total of 17 hours, how long did each one work?
2006-08-07 06:59:55 · 11 answers · asked by Phoenix 1 in Education & Reference ➔ Homework Help
let number of hour mac worked=x
so number of hours mary worked=x+5
x+x+5=17
2x=17-5
2x=12
x=12/2
x=6
so mac worked for 6 hours
mary worked for 6+5=11 hours
2006-08-07 08:15:14 · answer #1 · answered by flori 4 · 0⤊ 0⤋
Mary worked 11 hours and Mac worked 6 hrs.
11 + 16 = 17
16 - 11 = 5
Thus Mary worked 5 more hours than Mac.
2006-08-07 14:11:06 · answer #2 · answered by blueice_1820 2 · 0⤊ 0⤋
Mary worked 11 hours and Mac worked 6.
2006-08-07 14:05:23 · answer #3 · answered by midnight streaker 1 · 0⤊ 0⤋
mary worked 11 hours, mac worked 6
17 = 2x + 5
2006-08-07 14:05:17 · answer #4 · answered by combat_chuck_gurl 2 · 0⤊ 0⤋
Mac 6, Mary 11
2006-08-07 14:04:22 · answer #5 · answered by Uncreative Name 2 · 0⤊ 0⤋
mary worked for 5 hrs more,thus if the work done by mac is x then mary worked for x+5 hrs.
as total work =17 hrs,thus x(mac's work)+x+5(mary's work)=17
from there we get 2x=12,or x=6
thus mac worked for 6 hrs and mary for 11 hrs(6+5)
2006-08-07 14:12:07 · answer #6 · answered by Ashley. 3 · 0⤊ 0⤋
Mac = M
Mary = M + 5
M + (M+5) = 17
2M +5 = 17
Subtract 5 from both sides
2M = 12
Divide both sides by 2
M = 6
Therefore Mac worked 6 hours and Mary worked 11 (M + 5)
2006-08-07 14:07:23 · answer #7 · answered by Molly M 3 · 0⤊ 0⤋
mary worked 11 hours
mac worked 6
2006-08-07 14:03:33 · answer #8 · answered by trrocks03 3 · 0⤊ 0⤋
A + B = 17
B = A + 5
Therefore:
A + A + 5 = 17
2A = 17 - 5
A = 12/2 = 6
B= 11
6 + 11 = 17
2006-08-07 14:08:18 · answer #9 · answered by cherox 3 · 0⤊ 0⤋
Mary, the hard working, dedicated employee worked 11 h ours.
Her SCUM Sucking, lay about lazy slob of a co-worker, only worked 6, and probably goofed off the whole time, too!
2006-08-07 14:07:41 · answer #10 · answered by Marvinator 7 · 0⤊ 0⤋