= a2 + 2abi + b2 ?
Just can't remember and I am in the desert... (physically)
2006-08-05 22:46:52 · 15 answers · asked by just "JR" 7 in Science & Mathematics ➔ Mathematics
I think your wrong it should be
a^2 + 2abi - b^2
as i^2 = -1
2006-08-05 22:50:12 · answer #1 · answered by Matthew H 3 · 2⤊ 0⤋
Note i^2 = -1
(a + bi)^2 = (a+ bi)(a + bi)
= a^2 + 2abi + b^2 (i^2)
= a^2 + 2abi - b^2
= (a^2 - b^2) + 2abi
= (a + b)(a - b) + 2abi
2006-08-05 23:03:26 · answer #2 · answered by ideaquest 7 · 0⤊ 0⤋
(a + bi)(a + bi)
a^2 + abi + abi + (b^2 * i^2)
a^2 + 2abi + (b^2 * (sqrt(-1))^2)
a^2 + 2abi + (b^2 * -1)
a^2 + 2abi - b^2
if your problem was a^2 + b^2, then the factored form would be (a - bi)^2
2006-08-06 03:40:53 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
a^2 + 2abi - b^2
as i^2 = -1
2006-08-05 23:21:00 · answer #4 · answered by convert 2 · 0⤊ 0⤋
remember, i is the square root of -1
So i^2 = -1
(a + bi)(a + bi) = a^2 + abi + abi + b^2.i^2
= a^2 + 2abi + b^2.(-1)
= a^2 + 2abi - b^2
2006-08-06 20:56:53 · answer #5 · answered by Dive, dive, dive 2 · 0⤊ 0⤋
a^2-b^2+2abi because i^2=(-1)
2006-08-06 06:40:40 · answer #6 · answered by disco5z 1 · 0⤊ 0⤋
ok so
(a+bi)^2 = a^2 + 2abi +b^2.i^2
i = sqrt(-1)
i^2= -1
so
a^2+2abi - b^2 = (a+bi)^2
2006-08-07 22:16:43 · answer #7 · answered by narglar 2 · 0⤊ 0⤋
i^2 = -1
so a2 + 2abi - b2
2006-08-05 22:49:41 · answer #8 · answered by blind_chameleon 5 · 0⤊ 0⤋
it is a^2-b^2+2abi
2006-08-06 08:55:07 · answer #9 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
a2+2abi-b2
2006-08-05 22:50:53 · answer #10 · answered by Anonymous · 0⤊ 0⤋