IS THE EXPLOSION OF A CRACKER A CHEMICAL CHANGE EXPLAIN.
2006-08-05 21:22:34 · 7 answers · asked by SHAMBHU W 1 in Science & Mathematics ➔ Chemistry
we added fire to it
2006-08-05 21:36:36 · update #1
Tell us what you did to the cracker to make it explode and we'll tell you what the chemical changes were.
2006-08-05 21:30:33 · answer #1 · answered by druid 7 · 0⤊ 0⤋
A chemical change is a process in which reactants are changed into one or more different products. A chemical change occurs whenever new compounds are formed or existing compounds decomposed. During this reaction, chemical bonds between atoms are broken and new chemical bonds formed. This results in a rearrangement of the chemical bonds, thus differing from physical change which is a change of a substance's state (solid, liquid, gas).
2006-08-13 03:19:19 · answer #2 · answered by Kit 2 · 0⤊ 0⤋
By explosion of crackers chemical energy is converted into light energy.
2006-08-10 22:51:06 · answer #3 · answered by Tushar 2 · 1⤊ 0⤋
its chemical reaction as active chemicals get oxidised to rapid pace generating heat and sound. cracker ingredients are enclosed in a tight pack so that when chemical reaction takes place the smoke and heat generated rips open the pack. creates explosion
2006-08-10 22:49:55 · answer #4 · answered by raju 3 · 0⤊ 0⤋
a chemical reaction is one which cannot be brought back to its original state after its reaction takes place .
in the explosion of crackers the chemicals once after reaction cannot be brought back to its original form or substances originaly present in it .
hence it is a chemical change
2006-08-09 18:55:06 · answer #5 · answered by shailesh 1 · 1⤊ 0⤋
Yes. The cracker exploding comes from the rapid burning of it's contents, giving off large volumes of hot gases:
10 KNO3 + 3S + 8C → 2K2CO3 + 3K2SO4 + 6 CO2(g) + 5N2(g)
2006-08-12 00:45:31 · answer #6 · answered by Dyno 1 · 0⤊ 0⤋
Absolutely! Components of gunpowder are being Oxidized! Hope your not cheating on your homework! Its worth doing a little reading.
2006-08-13 18:01:54 · answer #7 · answered by Plato X 2 · 0⤊ 0⤋