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2006-08-05 19:06:39 · 43 answers · asked by Mark A 1 in Science & Mathematics Mathematics

43 answers

it's an imaginary number called i.

2006-08-05 19:10:09 · answer #1 · answered by Natalia 3 · 2 0

1

2006-08-05 19:09:38 · answer #2 · answered by Dude 4 · 0 1

Think for yourself: what is the definition of a square root? A square is a positive number, so you will need to find a number x say, that when multiplied by itself will produce -1. Do you think this is possible? The answer is no. The square root of minus 1 does not exist! In fact, the square root of any negative number does not exist. Complex analysis was built on the assumption that i^2 = -1 and special properties of trigonometric series.

2006-08-06 08:24:39 · answer #3 · answered by Anonymous · 0 0

I think it is an imaginary unit
Represented by 'i' in complex numbers.

By definition, the imaginary unit i is one solution of the quadratic equation


or equivalently

.
Since there is no real number that squares to any negative real number, we imagine such a number and assign to it the symbol i.

Real number operations can be extended to imaginary and complex numbers by treating i as an unknown quantity while manipulating an expression, and then using the definition to replace occurrences of i 2 with −1. Higher integral powers of i can also be replaced with −i , 1, i, or −1.

Square root of the imaginary unit
One might assume that a further set of imaginary numbers need to be invented to account for the square root of i. However this is not necessary as it may be expressed as a complex number:

2006-08-05 19:16:57 · answer #4 · answered by Anonymous · 0 0

square root of minus 1 is called " i " (This is an axiom* an accepted mathematical fact . It can't be proved. root of -1 is defined as i)

It all started with the solution to the quadratic equation x^2 + 1 = 0


and square root of minus 4 = 2i

square root of minus 9 =3i

square root of minus 16 = 4i

because we can write -16 as product of -1 and 16 ie (-1)*(16) and root of 16 is 4 and root of -1 is i so the answer (i)*(4) = 4i

*check the spelling of axiom it might be wrong.

2006-08-05 19:16:21 · answer #5 · answered by Anonymous · 1 0

Its i beacause their is no such thing as negatives square roots.when you have a negative square root its called an imagonary number so you but an i with that number. In this case the square root of 1 is 1 but since its the square root of negative one its 1i which is the same thing as i.

2006-08-05 19:15:03 · answer #6 · answered by ika 2 · 0 0

In a branch of maths, complex maths, a number has been defined such that it's square is -1. This number is called "i" or "j".

i^2 = -1

or (-i )^2 = -1

The "i" axis is drawn perpendicular to the normal number line through 0. thus 0 = 0i

The complex numbers then represent a point on this "complex plane"... and are written like 3+i4 etc.

There is a whole load of applications for complex maths including in ac current calculations.

2006-08-06 00:57:34 · answer #7 · answered by blind_chameleon 5 · 0 0

the square root of minus 1 is i (pronounced as ioata).it is an imaginary number.

2006-08-05 19:34:21 · answer #8 · answered by ritika d 2 · 0 0

It's an imaginary number, "i". Since no number times itself ever results in a negative number, there can be no answers to a square root of a negative number. However, sometimes it still must be done, so humans invented i, or the square root of negative one.

2006-08-05 20:20:03 · answer #9 · answered by beethovens_sixth 3 · 0 0

the square root of minus one is an imaginary number. It is known simply as i

2006-08-06 10:43:35 · answer #10 · answered by headcage 3 · 0 0

As far as ordinary, everyday numbers go, the square root of minus one does not exist. However, mathematicians find it useful to invent a completely new kind of number to fulfil that role. They decided to assume that such a root really did exist, and wrote 'i' to represent it. ('i' was chosen because it stands for "imaginary").

2006-08-06 05:59:11 · answer #11 · answered by Paul B 5 · 0 0

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