x^3*y^2=t^4/w
2006-08-05 16:03:03 · 9 answers · asked by demetria_nyree 2 in Science & Mathematics ➔ Mathematics
Divide both sides by x^3
y^2 = (t^4/w)/x^3
Simplify
y^2 = t^4/(wx^3)
Take the square root (sqrt) of each side
y = +/- sqrt(t^4/(wx^3))
y = +/- sqrt(t^4)/sqrt(wx^3)
y = +/- t^2/(xsqrt(wx))
y = +/- t^2 sqrt(wx)/(wx^2)
Answer: y = t^2 sqrt(wx)/(wx^2) or y = -t^2 sqrt(wx)/(wx^2)
2006-08-05 16:20:56 · answer #1 · answered by MsMath 7 · 0⤊ 0⤋
y^2 = (t^4 / w) / x^3
y^2 = (t^4 / w) * (1 / x^3)
y^2 = t^4 / (w * x^3)
y = plus or minus t^2 / x sqrt (w*x)
2006-08-05 16:22:23 · answer #2 · answered by ronix 1 · 0⤊ 0⤋
y = t^2/sqrt(w*x^3)
2006-08-05 16:34:34 · answer #3 · answered by amarie 3 · 0⤊ 0⤋
(x^3)(y^2) = (t^4) / (w)
'..divide both side by (x^3)...
y^2 = t^4 / (w)(y^2)
...square root both side...
y = t^2 / (w^1/2)(y)
2006-08-05 16:21:55 · answer #4 · answered by Imoet 2 · 0⤊ 0⤋
if by this you mean
x^3 * y^2 = (t^4)/w
y^2 = ((t^4)/w)/(x^3)
y^2 = ((t^4)/w)/((x^3)/1)
y^2 = ((t^4)/w)*(1/(x^3))
y^2 = (t^4)/(wx^3)
y = sqrt((t^4)/(wx^3))
y = ((t^2)/x)sqrt(1/(wx))
y = ±((t^2)/(wx^2))sqrt(wx)
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but if you meant
x^3 * y^2 = t^(4/w)
y^2 = (t^(4/w))/(x^3)
y = sqrt((t^(4/w))/(x^3))
y = ((t^2)/x)sqrt((t^(1/w))/x)
y = ((t^2)/(x^2))sqrt(xt^(1/w))
y = ±((t^2)/(x^2))sqrt(xt^(1/w))
2006-08-06 04:28:19 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋
y= (t^4/2w)/(X^3/2)
2006-08-05 16:08:41 · answer #6 · answered by Anonymous · 0⤊ 0⤋
non sense ques.
2006-08-05 16:47:28 · answer #7 · answered by Anonymous · 0⤊ 0⤋
IF IM CORRECT YOUR ANSWER IS ALREADY IN SIMPLEST FORM
2006-08-05 16:07:26 · answer #8 · answered by Anonymous · 0⤊ 0⤋
y = sqrt (all that other stuff)
2006-08-05 16:06:26 · answer #9 · answered by Anonymous · 0⤊ 0⤋