v = (1/3)s^2 h
Multiply both sides by 3
3v = s^2 h
Divide both sides by s^2
3v/s^2 = h
2006-08-05 08:14:42
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answer #1
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answered by MsMath 7
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h=2
2006-08-05 14:58:30
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answer #2
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answered by Anry 7
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v=1/3s^2h.you wantto make 'h' the subject.firstly rewrite with
'h' at the left i.e. 1/3s^2h=v,multiply both sides by 3 to get rid of the 1/3 on the LHS.so the equation reduces to s^2h=3v
now the unwanted quantity on the LHS is the s^2.to get rid of it divide both sides by s^2.now you can write the equation with
'h' as the subject h=3v/s^2 or if you like 3v(s)^-2
2006-08-05 23:43:21
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answer #3
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answered by raj 7
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v = (1/3)s^2 h
Multiply both sides by (3/1)
3v = s^2 h
Divide both sides by s^2
3v/s^2 = h
but if this is v = (1/3s^2) h
then h= 3v s^2, but i don't think you meant that.
2006-08-05 15:29:43
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answer #4
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answered by Turkleton 3
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v = (1/3) * s^2h
3v = 1 * s^2h
ln (3v) =ln (s^2h)
ln (3v) =2h * ln s ----> this is a rule of logs, ln a^b = b*lna
ln (3v) =h * 2ln s
h = ln (3v) / 2ln s
h = ln (3v) / ln (s^2)
2006-08-05 23:03:13
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answer #5
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answered by Anonymous
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3V/ s^2 = h
2006-08-05 14:52:54
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answer #6
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answered by crazed1511 1
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