What's the answer
2006-08-05 07:03:59 · 6 answers · asked by bergstromboy 1 in Science & Mathematics ➔ Mathematics
even easier: find the inverse of both sides:
1/[1/x + 1/y] = 1/[1/z]
1/[(y+x)/xy] = z And there, but i'll add one step to make it look pretty:
xy/(x+y) = z
2006-08-05 07:12:20 · answer #1 · answered by dubsnipe 2 · 0⤊ 0⤋
1/x + 1/y = 1/z
The common denominator is xyz
xyz(1/x) + xyz(1/y) = xyz(1/z)
Multiplying the equation by xyz
yz + xz = xy
The new equation after multiplication
z(y + x) = xy
extract the common factor (z) on the left side of the equation.
z(y + x)/y + x = xy/y + x
Dividing both sides by y + x
z = xy/y + x
The answer: z = xy/y + x
2006-08-05 14:22:01 · answer #2 · answered by SAMUEL D 7 · 0⤊ 0⤋
Multiply the equation by the LCD which is xyz
yz + xz = xy then factor
z(x+y) = xy the divide both sides by x+y
z = xy/ (x+y)
2006-08-05 21:18:29 · answer #3 · answered by MollyMAM 6 · 0⤊ 0⤋
1/z = 1/x + 1/y = (y + x)/xy
z = xy/(x + y)
2006-08-05 14:09:43 · answer #4 · answered by bpiguy 7 · 0⤊ 0⤋
(1/x) + (1/y) = (1/z)
multiply everything by xyz
yz + xz = xy
z(y + x) = xy
z = (xy)/(x + y)
ANS : (xy)/(x + y)
2006-08-05 23:04:33 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋
multiply the whole equation by xyz.
yz + xz = xy
z(y+x) = xy
z = (xy)/(y+x)
tadaaa!
2006-08-05 14:08:47 · answer #6 · answered by Goose 2 · 0⤊ 0⤋