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HEY GENIUS PPL, ANSWER THIS ----if R= [(30^65)-(29^65)] / [(30^64)+(29^64)]THEN ____?
SELECT ANY1 FROM 4 OPTIONS AND EXPLAIN UR ANSWER--
1)0
2)0.1
3)0.5
4)R>1.0

I WILL REPEAT VALUE OF R ,IT IS
R=[(30^65)-(29^65)]/[(30^64)+(...

hey ppl u have to solve this without calculators
, any1 can solve using calculator

ppl i dont know but can v use componendo and dividendo in here or any other formulae but it should be without calculators


by the way the answer is R >1.0
BUT PROVE IT THEN ONLY UR GENIUS WITHOUT CALCULATORS

2006-08-05 02:22:44 · 6 answers · asked by cooldude 2 in Science & Mathematics Mathematics

6 answers

Let me find a piece of paper... I'll get back with you.

◄Update #1► I worked on the problem a little and have gotten it down to an inquality in which R>1 but my work lacks rigor. It is not yet a proof. Maybe someone else will jump in a show me the way. Louise or Mathematician, are you there?

By the way, I let x = 29 and n = 64. I translated your expression into the more general expression where x ≥ 1.

(x+1)^(n+1) - x^(n+1)
――――――――― = R
(x+1)^n + x^n

Crimson01:
a^m ± b^m ≠ (a ± b)^m

◄Update #2►
Given

30^65 - 29^65
――――――― = R
30^64 + 29^64

If we let x = 29 and n = 64, then we have

(x+1)^(n+1) - x^(n+1)
――――――――― (1)
(x+1)^n + x^n

By the Binomial Theorem (BT) we can expand the numerator of (1) and arrive at the following equivalent rational expression

(x+1)^n + x^n + x(x+1)^n - x^(n+1) - x^n
――――――――――――――――― (2)
(x+1)^n + x^n

Also, by the BT, we can show

x(x+1)^n - x^(n+1) - x^n > 0

This implies that expression (2) is greater than the following

(x+1)^n + x^n
―――――― (3)
(x+1)^n + x^n

It is obvious that expression (3) is equal to 1. This gives expression (1) is greater than 1.

Therefore, R > 1.

Done.

2006-08-05 03:09:08 · answer #1 · answered by IPuttLikeSergio 4 · 0 0

R=1^65/59^64=1/something=less than 1 so the answer is probably 2

2006-08-06 07:37:17 · answer #2 · answered by Anonymous · 0 0

the answer cannot be >1 coz their is sub in numerator which will result something less than denominator .so,R will be less than 1infact less than 0.1.and you cannot use componendo and dividendo coz their should be an unknown value to eliminate ,not all should be numericals.

2006-08-05 02:37:36 · answer #3 · answered by brightstar 2 · 0 0

never mind, I'm stumped for now. I've got my rules mixed up, and btw, it IS > 1:
((30^65) - (29^65)) / ((30^64) + (29^64)) = 23.9522231

http://www.google.com/search?hl=en&lr=&q=%2830%5E65+-+29%5E65%29%2F%2830%5E64+%2B+29%5E64%29

I thought I knew how to answer this, but I appear to be of no help ;)

2006-08-05 02:34:31 · answer #4 · answered by Manny 6 · 0 0

5) None of the above.

2006-08-05 02:27:33 · answer #5 · answered by blind_chameleon 5 · 0 0

bs+crappola*10(-)truth=R>2.1

~your conclusion is wrong.

2006-08-05 02:33:43 · answer #6 · answered by Sick Puppy 7 · 0 0

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