If so, why?
2006-08-05 01:58:17 · 13 answers · asked by tangerine 7 in Entertainment & Music ➔ Celebrities
No - she's an ignorant conformist to outdated feminine steriotypes (i.e. being rich, blonde, pretty and dumb) and "popular" culture, who whores herself out and lives off her father's enterprise rather than making her own way in the world.
She's not good looking either. Plastic's ok for making household goods, not so great on a woman.
2006-08-05 02:06:45 · answer #1 · answered by Mordent 7 · 3⤊ 0⤋
No. FAR too stupid. Kill any desire before it could get started. Even if she was the most beautiful woman on the planet. Unfortunately, she's quite average looking.
Overall:
She's hideously repulsive.
2006-08-05 02:10:26 · answer #2 · answered by OraclewannaB 3 · 0⤊ 0⤋
No, she is a cheap s l u t...however, if I saw the top of her head bobbing up and down, I don't think I could stop her...just being honest
2006-08-05 02:05:41 · answer #3 · answered by Velociraptor 5 · 0⤊ 0⤋
Not me!! It's just that she has got a lot of money and that makes her remain in news all the time
2006-08-05 02:06:02 · answer #4 · answered by Anonymous · 0⤊ 0⤋
i really think that nicky is hotter than paris,paris just gets more attention.i would give paris a 3.5
2006-08-05 02:08:07 · answer #5 · answered by cool6nigerian 2 · 0⤊ 0⤋
as attractive as a road accident
2006-08-05 02:05:38 · answer #6 · answered by Anonymous · 0⤊ 0⤋
i don't comprehend..........possibly because of the fact of her physique or her blond hair .............yet she's gruesome, she does not have a exceptionally face: curiously like an sq........possibly because of the fact of her money!
2016-12-11 07:12:15 · answer #7 · answered by ochs 4 · 0⤊ 0⤋
Parts of her. I'm human.
2006-08-05 02:05:17 · answer #8 · answered by Anonymous · 0⤊ 0⤋
she's just ok for me....there's a lot worse than her....but her problem is she is a legend in her own mind...
2006-08-05 02:03:56 · answer #9 · answered by Rob 5 · 0⤊ 0⤋
yes, in a skanky kind of way.
2006-08-05 02:04:26 · answer #10 · answered by Ross 3 · 0⤊ 0⤋