a frog is in a well. the well is 30feet deep .during day it climbs up 3 feet and during night it falls 2feet down how many days does it take to come out of the well.
2006-08-04 19:54:07 · 13 answers · asked by brightstar 2 in Science & Mathematics ➔ Mathematics
Let's start it from his final day. On his final day, he will climb up 3 feet. He won't fall down anymore because he will reach the top.
30 feet - 3 feet = 27 feet
So, how many days does he need to climb up 27 feet?
Every day he climbs up 3 feet and falls down 2 feet, so he climbs up 1 foot. He needs 27 feet/ (1 feet/day) = 27 days to do the rest of his journey.
Total = 27 days + 1 day = 28 days
2006-08-04 21:48:26 · answer #1 · answered by r083r70v1ch 4 · 4⤊ 0⤋
The frog takes 27 days to reach up to 27 feet. Then in the day time, he climbs up 3 feet more to come out.
Therefore the answer is 28 days!
2006-08-05 03:02:18 · answer #2 · answered by Ameya 3 · 0⤊ 0⤋
After 27 days the frog will be up 27 feet. On day 28, he will go up the remaining 3 feet and be out. So 28 days.
2006-08-05 02:59:55 · answer #3 · answered by Anonymous · 0⤊ 0⤋
28
2006-08-05 04:32:51 · answer #4 · answered by sk_yahoo 2 · 0⤊ 0⤋
Frogs cannot climb out of wells!
However hard they try the wall will be slippery. Your hypothesis that the frog will climb 3 feet is wrong. Therefore, the answer is infinity. The frog will die in the well and decompose in the water unless anyone is kind enough to take away its body and bury it.
2006-08-05 07:27:22 · answer #5 · answered by Naval Architect 5 · 0⤊ 0⤋
28 days
2006-08-05 02:58:35 · answer #6 · answered by queStionmarK 2 · 0⤊ 0⤋
28 days
2006-08-05 02:57:38 · answer #7 · answered by Anonymous · 0⤊ 0⤋
On the 27th day it climbs the final 3 feet.
2006-08-05 03:00:55 · answer #8 · answered by druid 7 · 0⤊ 0⤋
27 days
2006-08-05 05:13:46 · answer #9 · answered by mmmm n 2 · 0⤊ 0⤋
31 days. Unless it starts in the night then 32.
2006-08-05 02:58:59 · answer #10 · answered by dlfield 3 · 0⤊ 0⤋