1) subtract 3k from both sides... 4 = k - 2
2) add 2 to both sides... 6 = k
Solution: 6 = k
2006-08-04 18:39:57
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answer #1
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answered by MB_Bailey 3
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4+3k=4k-2
Add 2 to both sides of equation:
4+3k(+2)=4k-2(+2)
The+and- 2's on the right side should cancel out, on the left side 4+2=6:
6+3k=4k
Subtract 3k from both sides of equation:
6+3k(-3k)=4k(-3k)
4k-3k=1k (or just "k"):
6=k
2006-08-04 18:44:04
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answer #2
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answered by Purechild 2
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every one can solve this question except some one who does not know math.
4+3k=4k-2
4 + 3k - 4k = -2
4 + - k = -2
-k = -4 -2
-k = -6
k = 6
2006-08-04 18:39:19
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answer #3
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answered by ___ 4
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k=6
2006-08-04 18:37:14
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answer #4
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answered by packermama 2
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6=k
2006-08-04 18:36:56
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answer #5
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answered by crystal 3
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4+3k=4k-2
4 + 3k - 4k = -2
4 + - k = -2
-k = -4 -2
-k = -6
k = 6
2006-08-04 23:14:01
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answer #6
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answered by yrzfuly 3
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4 + 3k = 4k -2
4+2=4k-3k
6=k
thus , k=6
cheers!
2006-08-04 18:40:26
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answer #7
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answered by peace 1
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addin 2 both the sides
(2)+4+3k=4k-2+(2)
6+3k=4k
6= -3k+4k
6=k
2006-08-04 19:10:09
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answer #8
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answered by BISWAJIT B 1
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4+3k = 4k-2
4 = 4k-3k-2
k-2=4
k=4+2
k=6
2006-08-04 18:44:31
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answer #9
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answered by marcus 1
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4+3k=4k-2
first bring k to one side and the numbers to the other
4k-3k=4+2
solving
1k=6
k=6
2006-08-04 20:19:31
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answer #10
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answered by R.PRASHANTH R 1
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