Five men and a monkey were shipwrecked on a island, and they spent the first day gathering coconuts.They piled them up together and then went to sleep for the night.
But when they were all asleep one man woke up, and he thought there might be a row about dividing the coconuts in the morning, so he decided to take his share. So he divided the coconuts into file piles. He had one coconut left over, and he gave that to the monkey, and he hid his pile and put the rest all back together.
By and by the next man woke up and did the same thing. And he had one left over and he gave it to the monkey. And all five men did the same thing, one after the other; each one taking a fifth of the coconuts in the pile when he woke up, and each one having one left over for the monkey.
And in the morning they divided what coconuts were left and they came out in five equal shares. Of course each one knew that there were coconuts missing but noone spoke up.
How many coconuts were there in the beginning?
2006-08-04
17:13:29
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5 answers
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asked by
Will
4
in
Science & Mathematics
➔ Mathematics
LOL. If I told you that the answer would be trivial. You can solve it without that knowledge.
Hint: It is an integer and has 5 or less digits.
2006-08-04
17:29:45 ·
update #1
Yes David. I ran out of room to describe the problem. Each person was only dividing the main pile into five equal piles (for the people) and then giving the one leftover coconut to the monkey.
2006-08-04
17:44:30 ·
update #2
Well done again pascal. Someone knows how to google the problem to get the answer.
Another solution though it is kind of odd is: -4
Each man divides the pile into 5 equal piles of -1 coconut each and then tosses the extra "positive" coconut to the monkey. He then takes out his "-1" coconut and returns the remaining -4 coconuts to the pile. Each man does and winds up with -2 coconuts (-1 in middle of night and -1 in morning) while the monkey gets a +6 coconuts.
2006-08-04
17:52:22 ·
update #3