(1/5)x - 2 ≥ (3/4)x + 5
Multiply everything by 20
4x - 40 ≥ 15x + 100
Add 40 to each side
4x ≥ 15x + 140
Subtract 15x from each side
-11x ≥ 140
Divide each side by -11 (notice that the inequality flips)
x ≤ 140/-11 or x ≤ -140/11
2006-08-04 17:01:36
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answer #1
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answered by MsMath 7
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Let's see. I'm not too sure whether you mean (1/5)x and (3/4)x or 1/(5x) and 3/(4x).
If you mean the first, all you need to do is isolate x. You have:
(1/5)x - 2 ⥠(3/4)x + 5
-2 ⥠(11/20)x + 5
-7 ⥠(11/20)x
-140/11 ⥠x
in which case the sign never changes because you only add and subtract and multiply by a positive number (e.g. 20/11)
Of course, if instead, you mean:
1/(5x) - 2 ⥠3/(4x) + 5
We have two cases: x > 0 and x < 0. x â 0 because otherwise the denominator would be 0.
If x > 0, we multiply by the LCD = 20x. Because it's positive, we don't change signs:
4 - 40x ⥠15 + 100x
-11 ⥠140x
-11/140 ⥠x
and there is no answer because
{x | x > 0} U {x | x ⤠-11/140} = Ã
meaning x cannot be greater than 0 (our assumption) and less than or equal to -11/140
In the second case, if x < 0, we have:
4 - 40x â¤15 + 100x (sign changes because 20x < 0!)
-11 ⤠140x
-11/140 ⤠x
in which case we have:
{x | x < 0} U {x | x ⥠-11/140} = {x | -11/140 ⤠x < 0}
And our answer is any number in which
-11/140 ⤠x < 0
2006-08-05 00:01:52
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answer #2
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answered by tedjn 3
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Testing the answers:
With (+140/11)
(1/5)(+140/11) - 2 = .54545
(3/4)(+140/11) +5 =14.545454
With (-140/11)
(1/5)(-140/11) - 2 = -4.54545
(3/4)(-140/11) +5 = -4.545454
So (-140/11) satisfies the "=" requirement
Now for less-than or greater-than:
(-141/11) is < (-140/11) and
(1/5)(-141/11) - 2 = -4.5636 which is > (3/4)(-141/11)+5 = -4.61364
So x <= (-140/11) looks correct to me.
Answer number 1
2006-08-05 00:27:59
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answer #3
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answered by John G 3
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1/5(x) - 2 ⥠3/4(x) + 5
1/5(x) - 3/4(x) ⥠7
1/5, 3/4
1/5 = 4/20
3/4 = 15/20
4/20(x) - 15/20(x) ⥠7
-11/20(x) ⥠7/1
x ⤠(7) / [-11/20]
x ⤠[7/1] * [20/-11]
x ⤠140/-11
x ⤠-140 / 11
So, the answer is #1.
2006-08-05 00:16:26
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answer #4
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answered by Anonymous
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the first one is correct...
x ⤠-140/11
2006-08-05 00:02:08
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answer #5
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answered by ? 2
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I think it's true or false depending on the value of x
2006-08-04 23:59:53
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answer #6
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answered by Mr. Sly 4
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answer 1 is what i got
2006-08-05 00:04:29
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answer #7
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answered by Anonymous
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3... definately
2006-08-04 23:59:35
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answer #8
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answered by airforceterp330 3
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The answer is purple.
2006-08-05 00:01:51
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answer #9
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answered by mnorth12 3
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number one. this one i solved in my head easily...
2006-08-05 13:56:55
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answer #10
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answered by Anonymous
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