2006-08-04 16:28:40 · 10 answers · asked by Kurse 3 in Entertainment & Music ➔ Comics & Animation
I think roadrunner is probably faster than quicksilver. If they were fighting hes got this 'uncanny luck' that would probably play in his favor. And if they were racing, I think that one of Coyote's traps would accidentaly be set off against quicksilver
2006-08-05 03:15:52 · answer #1 · answered by Ziggy27 2 · 3⤊ 2⤋
Very good question since they are both faster then the speed of sound and nothing more. However, one might say that the Roadrunner might win since he's the good guy and always wins and some might say that Quicksilver will win since he has a huge ego and likes to cheat when he can't win something fair and square and he's the son of Magneto after all, he wouldn't let a bird win instead of him in a race.
Winner: Depends on who you like better since they both have the same speed
2006-08-05 13:18:07 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Quicksilver.
2006-08-05 00:49:44 · answer #3 · answered by Kiyura 4 · 0⤊ 0⤋
I just saw a baby Roadrunner the other day. It was so cute, so I vote for Roadrunner.
2006-08-04 23:46:36 · answer #4 · answered by papricka w 5 · 0⤊ 0⤋
Quicksilver... my favourite marvel character. But he isn't just fast, he also thinks quickly too so I think he can come up with even better traps than that coyote.
2006-08-05 00:27:03 · answer #5 · answered by ♥☆ Star ☆♥ 4 · 0⤊ 0⤋
quicksilver! im a roxy girl
2006-08-04 23:33:32 · answer #6 · answered by burnedpopcorn 1 · 0⤊ 0⤋
Roadrunner can outwit Pietr any day. (Tell me thay haven't changed the name on me!)
2006-08-05 01:03:40 · answer #7 · answered by matt 3 · 0⤊ 0⤋
Depends. Do they have to run through a mountain with a cave painted on the side of it?
2006-08-04 23:32:28 · answer #8 · answered by themikejonas 7 · 0⤊ 0⤋
The Big Shot would kick Kurse's a** and his boyfriend Francisc.
2006-08-05 08:51:19 · answer #9 · answered by The Big Shot 6 · 0⤊ 0⤋
roadrunner, he has that acme credit line
2006-08-04 23:35:59 · answer #10 · answered by conanamor 2 · 0⤊ 0⤋