English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Its a small pool 10' diameter and approxiametly 30" depth.

2006-08-04 15:30:18 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

There are 231 cubic inches to a gallon.

To solve this problem, we need to know the area of the water surface of the pool.

Radius is 1/2 the diameter, so 5' = radius.

5' = 60 inches

Area = pi * radius^2
Area = 3.14 * 60^2
Area = 11 304 sq. inches.

Simply multiply this by the depth of the pool to find the volume.

Area * height = volume
11 304*30 = 339,120 cubic inches
Volume = 339,120 cubic inches

Now we convert cubic inches to gallon.

There are 231 cubic inches to a gallon, so

339,120/231 = 1 468.05195 Gallons

You have about 1,468 gallons in the pool.

2006-08-04 15:38:12 · answer #1 · answered by polloloco.rb67 4 · 0 0

The volume of a gallon of water is 231 cubic inches.
Convert your diameter to inches: 10 feet = 10 x 12 =120 inches so radius = 60 inches
The volume of your pool is a cylinder: (pi)(r^2) h =
3.14 x 60^2 x 30 = 339120 cubic inches

To get the number of gallons: 339120/231=1468.05 gallons

2006-08-04 15:49:01 · answer #2 · answered by G.V. 6 · 0 0

Formula is pi*r^2*h

60^2*pi*30 = 339,292.007 cubic inches = 1,468.79656 gallons

2006-08-04 15:34:15 · answer #3 · answered by Anonymous · 0 0

so, its a circular pool.
just see it as a cilindar!
pi r ^2 times h
pi x
339,292 square inches of water
then just convert that to gallons
or watever

2006-08-04 15:55:31 · answer #4 · answered by Eng 5 · 0 0

fedest.com, questions and answers