and a pressure of 750torr to occupy a volume of 0.75L. What is the temp at which it will burst if the pressure is 755torr at the time it breaks?
2006-08-04 07:29:42 · 2 answers · asked by classysexyrich 1 in Science & Mathematics ➔ Chemistry
a. 787K
b. 111K
c. 776K
d. 109K
2006-08-04 08:03:14 · update #1
or similar to how the other guy did it.. but i find it easier to understand that if the pressure multiplyed by the volume divided by the temperature is the same on both sides of the equation
so in essence P1V1/T1 = P2V2/T2 so if ur p1 =750
ur volume = 2
temp = 293
so u get 750*2/293
then ur other side u work it out lol...
ok p = 755 v= 0.75 t=?
so u get 1500/293 = 755*0.75/?
so u end up with t= 755*0.75/(1500/293)
lol ok u just put that in a calculator and u will get the answer.
and from ur options i got 111k.. its 110.6 but u round it up.
2006-08-04 11:17:53 · answer #1 · answered by Anonymous · 1⤊ 0⤋
This is an application of the Ideal Gas Law, PV = nRT
Assuming you don't add more gas in the process, you can rearrange the equation to:
P*V/T = n*R, where n*R doesn't change
thus, P1*V1/T1 = P2*V2/T2
P1 = 750 torr
V1 = 0.75 liters
T1 = 293K
P2 = 755 torr
V2 = 2.0 liters
T2 = ? K
since you are solving for T2, rearrange the equation again to get:
T2 = P2*V2*T1/(P1*V1) = ?
and I will let you do the arithmetic.
2006-08-04 08:54:53 · answer #2 · answered by Dave_Stark 7 · 0⤊ 0⤋