A 3.20cm3 air bubble forms in a deep lake at a depth where the temp is 8C at a total pressure of 2.45atm....?

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A 3.20cm3 air bubble forms in a deep lake at a depth where the temp is 8C at a total pressure of 2.45atm....?

The bubble rises to a depth where the temp and pressure are 19C and 1.12atm. Assuming the amount of air in the bubble has not changed calculate the new volume.

2006-08-04 07:22:13 · 2 answers · asked by hiklass07 1 in Science & Mathematics ➔ Chemistry

a. 1.52cm3
b. 7.27cm3
c. 1.43cm3
d. 6.25cm3

2006-08-04 07:58:57 · update #1

2 answers

The equation, derived from PV=nRT is

PV/T (for situation 1) = PV/T (for situation2)

Use the correct units.

2006-08-06 13:36:15 · answer #1 · answered by Peter Boiter Woods 7 · 0⤊ 0⤋

Please, do your own homework.

2006-08-04 14:28:34 · answer #2 · answered by Jeffrey S 6 · 0⤊ 0⤋