240 volts on the secondary and 2.5 amps are flowing in the primary, what is the secondary current?
a. 50 amps
b.75 amps
c. 138.72 amps
d. 150 amps
2006-08-04 06:26:39 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Physics
here we can apply the relation:
Vp/Vs = Is/Ip where
Vp = voltage in the primary coim
Vs = voltage in secondary coil
Ip = current in primary coil
Is = current in secondary coil
therfore:
7000/240 = Is/2.5
Is = 72.91 amp
i hope u got ur point from my explanation
2006-08-04 11:38:09 · answer #1 · answered by Kevin 5 · 0⤊ 0⤋
Assuming there is no loss,
the primary has the power consumption of:
7000 * 2.5 = 17500 watts.
If the secondary is wound for 240 volts, the current necessary to consume 17500 watts is:
17500 / 240 = 72.92 amps.
2006-08-04 13:31:32 · answer #2 · answered by tkquestion 7 · 0⤊ 0⤋
Well, assuming the transformer is ideal, the answer would be 72.92 amps. But no transformer is ideal, so the actual current would be LESS than that. So actually, it would probably be A, not B, even though B is closer. 50 amps would mean a 69% efficiency, which is fairly standard for many transformers.
2006-08-04 16:49:40 · answer #3 · answered by J C 3 · 0⤊ 0⤋
choice B i.e.75 amps
2006-08-04 13:41:24 · answer #4 · answered by raj 7 · 0⤊ 0⤋
power can't be created from nothing.
7,000 * 2.5 = 240 * I
I = 72.9 amps.
2006-08-04 13:33:41 · answer #5 · answered by the redcuber 6 · 0⤊ 0⤋
73.92 amps, so B is the closest answer
2006-08-04 13:33:15 · answer #6 · answered by Amphibolite 7 · 0⤊ 0⤋
goo goo ga ga goo
2006-08-04 13:29:51 · answer #7 · answered by tearsnomore2005 2 · 0⤊ 0⤋