Is there a point on the axis of rotation of the earth at the poles , where the speed of rotation is zero?

Question

The earth is a globe.A point on the equator completes one circle in 24 (roundly). As we move towards the axis of rotation at the pole in a strait line from any point on the equator , the speed of ratation should be progressivley reducing in such a manner , that it should be zeero at the center of the axis of rotation. The earth being a solid , compact mass , if there is such a fixed point at the axis that does not rotate , the earth itself would not rotate. But the earth rotates and there is no real fixed axis running through its center . What happened to the spot where the speed should necessarily be zeero ? A real fixed point at the pole will not allow the earth to rotate .How can we reconcile this position?

In physical reality , it appears that there is not and there can not, be a point in the axis of rotation of the globe where the speed is zero. But in reality there is , though it is invisible. Because on the other side of the central point the ponts move in theopposite direction and with gradually increasing speed .Only where there is no matter existing at the central point, there will be no rotation as it will be empty with no matter in it attached to the global body.This vacuum exists in the atoms that make up the matter itself , and they align in the line of the axis when the globe spins.. The theorical positon is practically existing also.

Answer 1

No there isnt
the simple reason being, Earth is Flatter at poles and hence... you know the rest rt..

Answer 2

The tangential velocity of a particle within the earth determined by the earth's rotation is
defined by the distance in miles it travels in 24 hours divided by 24. The answer in m.p.h. The distance it travels
is on a circumference of a circle defined by c=pi(d) where d is the distance to the axis of the earth. A point on
the axis has zero distance so it seems that the tangential velocity is zero. But that's math. In physical reality even an electron, the smallest particle, has a measurable diameter. So even an electron rotates if it were at the axis.

Answer 3

in simple terms for example, right it quite is the formula for centripetal acceleration: a=v^2/r a=(463.9)^2/6378750m a=0.0337m/s^2 g=9.8m/s^2 a is 0.34% of g. it quite is at sea point on the equator. This value will immediately get smaller as your selection will advance, because of the fact the two the radius of rotation AND the linear velocity shrink. (no rely the place you're, it takes 24hrs to make a million finished holiday). not basically that, yet as your selection will advance, the path of "centrifugal stress" is way less and much less consistent with the path of gravity, so this rapidly reducing stress could have a rapidly reducing proportion of its result on your weight. In different words, it turns into negligible very immediately. For Chicago, (assuming a around Earth) the relief in acceleration simply by Earth's rotation is .025m/s * cos(selection) = 0.019 m/s^2, or 0.19% Earth might might desire to rotate as quickly as each and every eighty 4.40 8 minutes as a manner to make you weightless on the equator.

Answer 4

If a point is at a distance d from the axis of rotation, it's speed is d*omega where omega is the speed of rotation. omega is a constant.

Now at the axis of rotation itself, d=0 so the speed is also zero. You could say that the speed of rotation is undefined at the axis of rotation since it's 0/0. But that's a weired way of seeing it. Even if d is very small, say a nanometer, the equation omega = speed/d holds and omega is the same everywhere. So for convenience we say that omega has the same value (one revolution per 24 hours) at the axis of rotation as well.

Answer 5

here the angular velocity is same in all the case

if the distance between the axix to the point is zero then there is no velocity.
it can be verified by using the formula the linear velocity can be calculated as
v = W*r
where v = (linear/ tangential) velocity (= distnace moved / time taken)
w = angular velocity (= angles revolved / time taken)
and r = radius ( = distance between the axis to the point)

so if r=0 then v = 0
so possible...

at the axix of rotation the linear (tangential) velocity is zero

infact it wont move just rotate... it has angular velocity but not linear velocity...

Answer 6

no. A point has no dimensions and can thus not rotate around its axis

Answer 7

earth doesn't rotate on only 1 axis.